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Do a E1 elimination reaction (using a weak base, such as a hot alcohol).  The initial primary cation formed is unstable, and a methyl shift will result in a more stable secondary cation.  Elimination of the tertiary proton will give you 2-methyl-2-butene as the major product (zaitsev's rule - it is the more substituted product).  Elimination of the primary proton will also get you some amount of 3-methyl-1-butene (the hoffman product).

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14y ago
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6mo ago

The formation of 2-methyl-2-butene from the dehydration of neopentyl alcohol involves the removal of a water molecule. Neopentyl alcohol has three hydroxyl groups, and one of them is lost during the dehydration process, resulting in the formation of 2-methyl-2-butene as the final product. This reaction typically requires the use of an acid catalyst, such as sulfuric acid.

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Q: Formation of 2-methyl-2-butene from dehydration of neopentyl alcohol?
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