The voltage remains the same across the circuit as it is a parallel connection. So, the current across the upper half of the circuit where the ammeter is connected is calculated as I = V/R = 12.04 (total voltage)/12 (Resistance R1) = 1 A. Hence, the ammeter will read 1 A.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
the bulb will glow and ammeter will show the reading
An ammeter or a voltmeter gives the reading of the flow of current, which is due to the movements of ions. When a rusted nail is immersed in the solution it will add the no of ions into the solution. This will increase the ion concentration and therefore will change the reading of a voltmeter and ammeter.
In a series circuit, the current is the same throughout all components. Therefore, both ammeter 1 and ammeter 2 will read the same current, as they are measuring the same flow of electrons in the circuit. The readings on both ammeters will be equal, so neither will have a bigger reading. The voltage drop across the lamps may differ, but that does not affect the ammeter readings.
Assuming the new lamp is in series, the ammeter reading falls because the total resistance has increased. By how much depends on how the lamp resistance depends on voltage. If the lamp is added in parallel to the first, then the ammeter reading doubles.
An open switch in a circuit will stop all current flow so the ammeter should read zero amps.
v on a ammeterusually means Volts
The decrease of light intensity on an LDR will cause the resistance of the LDR to increase, which will result in a decrease in current flow through the circuit. As a result, the ammeter reading will decrease.
The value of the amplitude of an electric current is measured in amperes (A) using a tool called an ammeter. The ammeter is connected in series with the circuit to measure the flow of current. The reading on the ammeter displays the amplitude value of the current.
Connecting an ammeter does not reduce the frequency errors.
The answer to this depends on where the ammeter is in the circuit. Assuming the ammeter is in series with the bulb and no other objects are attached, then the current is 0.4 Amps. Otherwise, your question is unanswerable without more information.
You have to do the experiment you have been asked to do to find out.