0
What else can I help you with?
What happen when ammeter connected in parallel?
an ideal ammeter has zero or negligible resistance when this is connected in series no effective resistance would be added in the circuit so that the value of curret that we get is exactly of the circuit only. but when the ammeter is connected in parllel as it has zero resistance , the resistor to which it is connected in parllel gets shorted and due to his the effective resistance of the circuit is changed and so the effective current ... due to this the w=value measured by the ammeter would be different (incresed due to dec. in effective resistance)
What would happen if a voltmeter were substituted for an ammeter?
Smoke. Since a voltmeter is in parallel with the load it is right across the source voltage. Putting the amp meter across the line with its low resistance it will act like a fuse, hence the smoke. Newer solid state testers are usually smarter that the operators. They have built in circuitry which sense the wrong settings you are using and shut the tester off with a "beep" to let you know that you are doing something wrong.
Why are there more than two terminals on some ammeters and voltmeters?
A volt meter needs a high internal resistance not to influence the measurement, an ammeter needs a low internal resistance. Sometimes the easiest way to make that happen is to have different connectors.
When an AC 5A and dc Current of 5A applied simultaneously to the circuit then what it happen?
A DC ammeter will read zero
What will happen if a voltmeter has a low shunt resistance instead of having high shunt resistance?
The purpose of a voltmeter is to indicate the potential difference between two points in a circuit.When a voltmeter is connected across a circuit, it shunts the circuit. If the voltmeter has a low resistance,it will draw a substantial amount of current. This action lowers the effective resistance of the circuit andchanges the voltage reading.
What will happen if the reading of ammeter a2 after passing through 30 ohm resistance if reading of a1 is 3A after passing through 20 ohm resistance if both are parallel to each other?
5 A
What will happen if ammeter is put across a resistance in a circuit?
Maybe blow the fuse or burn out the wiring. An ammeter has an extremely low resistance. connecting it across the resistance causes the resulting parallel resistance to be slightly lower than the resistance of the ammeter 1/Rt = 1/R + 1/R(ammeter)
What will happen to the reading on the ammeter if one bulb blows out?
If one bulb in a series circuit blows out, the circuit becomes open, and the current stops flowing. As a result, the reading on the ammeter will drop to zero since there is no current passing through the circuit. In a parallel circuit, if one bulb blows out, the current may decrease slightly due to the change in total resistance, but the ammeter will still show a reading corresponding to the remaining bulbs in operation.
What happen to voltage and current when rheostat is adjusted from maximum to minimum resistance using both ammeter and voltmeter?
When a rheostat is adjusted from maximum to minimum resistance, the overall resistance in the circuit decreases. As a result, the current flowing through the circuit increases, which can be observed on the ammeter as a higher reading. Conversely, the voltage across the rheostat will decrease, as the voltage drop across a lower resistance is less, which can be monitored using the voltmeter.
What happen when ammeter connected in parallel?
an ideal ammeter has zero or negligible resistance when this is connected in series no effective resistance would be added in the circuit so that the value of curret that we get is exactly of the circuit only. but when the ammeter is connected in parllel as it has zero resistance , the resistor to which it is connected in parllel gets shorted and due to his the effective resistance of the circuit is changed and so the effective current ... due to this the w=value measured by the ammeter would be different (incresed due to dec. in effective resistance)
What will happen to speed-torque characteristics of an induction motor is the rotor resistance is increased?
If Rotor resistance is increased torque is increased
What happen to resistance if length is increased?
it increases
What would happen if a voltmeter were substituted for an ammeter?
Smoke. Since a voltmeter is in parallel with the load it is right across the source voltage. Putting the amp meter across the line with its low resistance it will act like a fuse, hence the smoke. Newer solid state testers are usually smarter that the operators. They have built in circuitry which sense the wrong settings you are using and shut the tester off with a "beep" to let you know that you are doing something wrong.
What happen to the current in a circuit if the resistance is increased?
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
What will happen to a light dependant resistor of the resistance is increased?
Your question seems to have an idea in it backwards.
What will happen if you connect the ammeter in parallel with the component?
All the current would go through the ammeter. The whole purpose for making a measurement with an ammeter is to determine current draw through a component or circuit. If the ammeter takes all the current away from the device under test, the reading would be meaningless. Also, since the ammeter would present pretty much a dead short to the power supply, blown fuses or toasted components usually result.
What will happen if the voltmeter was inserted in place of an ammeter?
You would load the circuit, and it is likely it would not operate correctly. A volt meter is designed to have a very high resistance between the two probes; an ammeter is designed to have a very low resistance. For instance, say you have a 120 watt light bulb that runs on 120 volts (you would then draw ~1 amp of current). If you tried to measure this with a meter that has .1 ohm resistance on ammeter setting, and 1,000,000 ohms on volt meter: Error due to loading: ammeter: .1 / (120 + .1) = .08%; Current will be .999Amps, power to the light bulb will be 119.9 watts Volt meter: 1,000,000/ (120 + 1,000,000) = 99.9%; current will be 120micro Amps, power to the light bulb will be 14.4 milliwatts (the light bulb will not appear to be on).
