If resistance is increased, current decreases.
Ohm's Law: current equals voltage divided by resistance.
a circuit with no resistance or zero resistance can be considered as open circuit in which the current is zero. without resistance the circuit just becomes open ()
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
When the thermistor in the circuit is heated, its resistance decreases due to the negative temperature coefficient of thermistors. This reduction in resistance allows more current to flow through the circuit. As a result, the increased current causes the lamp to receive more power, leading to a brighter illumination.
If a bulb with higher resistance is used in a simple circuit, the total resistance in the circuit would increase. According to Ohm's Law (V=IR), with an increase in resistance, the current in the circuit would decrease since the voltage supplied remains constant.
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
The current is greater than or equal to (6) divided by (the effective resistance of the circuit).
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
If resistance in a circuit increases, the current flowing through the battery decreases according to Ohm's Law (I = V/R). This reduction in current can lead to lower power output and may cause the battery to operate less efficiently. Additionally, higher resistance can result in increased heat generation at the resistive element, potentially affecting the battery's performance and lifespan. In extreme cases, if the resistance is too high, the circuit may not function at all.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
In what sense.