Study guides

☆

Q: How many grams of magnesium ion are in 155.0 grams of Mg3P2?

Write your answer...

Submit

Related questions

1550 grams = 3.4171300 pounds

Mg3P2 contains two atoms of phosphorous.

About 3.42lbs.

54.67 oz

That is approximately 6.834 cups.

One mole of magnesium is equal to 24 grams. So 0.348 will be 24 * 0.348 = 8.352 grams of magnesium.

520 calories and 34 grams of fat. It has 1550 grams of sodium.

i dont know help :C

Magesium phosphide (Mg3P2) has 5 atoms: 3 from Mg and 2 from P.

Theoretically the mass is 62,3018 g.

24 grams

1,11 moles of magnesium have 26,97855 g.

There are 0.13 moles in 20 grams of magnesium nitrate.

1550 kj @ 1 mol / 2658 kJ = 0.5831 moles of butane

Magnesium: 12,06 gOxygen: 15,88 g

88,1 moles of magnesium is equivalent to 2 141,27 g.

88,1 moles of magnesium is equivalent to 2 141,27 g.

24 / 40 = x / 4.00 x = 2.4 g Mg

About tree fiddy

E. 0.0214 mol

A lot

1.25 x 1023

24

Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================

1.269