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You need 26,49 g silver nitrate.
137.5 gm
To solve this, we will figure out how many grams there are per litre. To do this, we will divide the overall amount of litres 350 grams goes into by 350, so we are dividing 350 by 10,000. This answer is 0.035. We will then multiply 0.035 (how many grams needed for one litre) by 3300, to get how many are needed for that many litres, which gives us 115.5 grams. 115.5 grams are needed for 3300 litres if 250 grams are needed for 10,000 litres.
769.0 grams
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
16,45 g nitrogen are needed.
A US pint is 473 grams. - An Imperial pint is 568 grams
16.0 g
30 grams
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
The number of grams of ore that is needed to obtain 454.0 grams of Fe is 1297 grams. The answer was achieved by dividing 454.0 grams by 35 percent.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?