N2(g) + 3H2-> 2NH3(g) This is the balanced equation
Note the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2 This will be important.
moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present
moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present
Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.
moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced
grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced
NOTE: The key to this problem is recognizing that N2 is limiting, and therefore limits how much NH3 can be produced.
First write down the balanced reaction eq'n
N2(g) + 3H2(g) = 2NH3(g)
We note the molar ratios are 1:3::2.
We have 12.11 g (H2)
Convert to moles
Mol(H2) = 12.11/2 = 6.055 moles Equivalent to 3 moles in reaction equation.
Hence
moles(NH3) = 6.055 x 2 / 3 = 4.03666... moles Equivalent to 2 moles of NH3
Mass(NH3) = 4.036666... X ( 14 + 3) = 4.036666.... x 17 = 68.623333... g
Done!!!! Hope that helps!!!!
The answer is 20,664 g ammonia.
The mass of ammonia will be 95,03 g.
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
The mass of ammonia is 147,5 g.
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
76 g ammonia are obtained.
89,6 g ammonia are obtained.
The mass of nitrous oxide is 262,8 g.
0,044 moles of NH3 can be produced.
Ok, so I'm assuming that the chemical formula is written as - 3H2 + N2 ----> 2NH3 2.80 = moles of N2 17.03052 g/mol = Molar mass of NH3 (2.80 mol N2) x (2 NH3) / (1 N2) = 5.6 mol NH3 x (17.03052 g) / (1 mol NH3) = 95.4 g NH3
394.794 grams
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?