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How many grams of copper sulfate would you heat to produce 29.8g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
What is the balanced equation for CuSO4?
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
What happens when CuSO4 reacts with H2O?
Copper sulfate dissolves in water, it does not react.
Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
Equation for when copper oxide reacts with sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
Do a 5m cuso4 and 5m cuso4 5 h2o contain the same quantities of cuso4?
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
How many grams of copper sulfate would you heat to produce 29.8g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
Balance Copper 2 sulfate pentahydrate is heated to drive off the water hydration?
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
What is the balanced equation for CuSO4?
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
What are 5 examples of electrolyte?
H2O CuSo4 Ca2So4
What is the balanced ionic equations for CuSO4 plus H2O reactions?
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.
What is the balanced chemical equation for copper and sulfuric acid react to form copper (II) sulfate and water and sulfur dioxide?
CuCO3(s) + H2SO4(aq) → CuSO4(aq) + CO2(g) + H2O(l)
What happens when CuSO4 reacts with H2O?
Copper sulfate dissolves in water, it does not react.
Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
Equation for when copper oxide reacts with sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
Molecular weight of CuSO4?
CuSO4 x 5 H2O is the formula for Copper Sulfate Pentahydrate.
