penta = 5
copper(II) sulphate pentahydrate =
CuSO4*5 H2O
CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
It becomes a non-crystalline, powdery anhydrous salt.The hydrated (pentahydrate) form is chalcanthite, a bright blue crystal. The rare anhydrous ore form is called chalcocyanite, a gray or pale-green powdery rock.(If heated to 650 °C, copper sulfate becomes copper oxide and sulfur trioxide.)
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
The most common form is the pentahydrate.
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
No, copper II sulfate pentahydrate does not sublime. Sublimation is the process of a substance transitioning directly from a solid to a gas without passing through the liquid phase, and copper II sulfate pentahydrate decomposes before it can sublime.
When water is added to anhydrous copper sulfate, it forms copper (II) sulfate pentahydrate, a blue crystalline solid. So, the color change observed is from white (anhydrous) to blue (pentahydrate) when water is added.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
Each molecule of copper(II) sulfate pentahydrate contains one copper atom, one sulfur atom, four oxygen atoms, and five water molecules. So, one molecule of copper(II) sulfate pentahydrate contains a total of 11 atoms.
Yes, copper (II) sulfate pentahydrate is an ionic compound. It is composed of positively charged copper ions (Cu^2+) and negatively charged sulfate ions (SO4^2-) held together by ionic bonds.