penta = 5
copper(II) sulphate pentahydrate =
CuSO4*5 H2O
CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
Describe the appearance and odor of the liquid obtained by heating copper II sulfate pentahydrate.
The reaction is dehydration.
The percentage of water in copper(II) sulfate pentahydrate is 36,04 %.
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. If you add water to the anhydrous copper sulfate an exothermic reaction occurs, you can feel the test-tube getting hot, as the blue copper sulfate pentahydrate is re-formed.
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
a copper sulfate solution it becomes copper (II) sulfate pentahydrate
The primary hydrate of copper sulfate is the pentahydrate of copper (II) sulfate, with formula CuSO4.5 H2O.
Describe the appearance and odor of the liquid obtained by heating copper II sulfate pentahydrate.
Yes it is
Physical
Dehydration and hydration of copper sulfate certainly is reversible. This is because the process can happen and be reversed and happen again.
The reaction is dehydration.
This is copper(II) pentahydrate or cupric sulfate or blue vitriol.
It becomes a non-crystalline, powdery anhydrous salt.The hydrated (pentahydrate) form is chalcanthite, a bright blue crystal. The rare anhydrous ore form is called chalcocyanite, a gray or pale-green powdery rock.(If heated to 650 °C, copper sulfate becomes copper oxide and sulfur trioxide.)
The percentage of water in copper(II) sulfate pentahydrate is 36,04 %.
The most common form is the pentahydrate.