The reaction is dehydration.
No, it is not a chemical reaction. The added heat only drives the water molecules out of the crystal structure. No bonds are made or broken. Actually, it is a chemical change, because there are bonds between the water and CuSO4. by heating, these bonds are broken, there is a color change not coming from the reactant.
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
The chemical formula for copper sulfate is CuSO4. Copper sulfate can form different hydrates by binding with varying amounts of water molecules. For example, copper (II) sulfate pentahydrate has a chemical formula of CuSO4·5H2O.
When copper sulfate pentahydrate is heated, the water molecules are driven off, leaving anhydrous copper sulfate as the solid residue. The chemical equation for this reaction is: CuSO4*5H2O(s) → CuSO4(s) + 5H2O(g).
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
No, it is not a chemical reaction. The added heat only drives the water molecules out of the crystal structure. No bonds are made or broken. Actually, it is a chemical change, because there are bonds between the water and CuSO4. by heating, these bonds are broken, there is a color change not coming from the reactant.
The chemical equation for the dissolution of copper(II) sulfate pentahydrate in water is: CuSO4 5H2O (s) Cu2 (aq) SO42- (aq) 5H2O (l)
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.
The reaction between silver (Ag) and copper sulfate (CuSO4) is a single displacement reaction. This is because the silver displaces the copper in the compound, resulting in the formation of silver sulfate and copper metal.
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
formula : cuso4 chemical name: copper sulphate
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).