No, it is not a chemical reaction. The added heat only drives the water molecules out of the crystal structure. No bonds are made or broken.
Actually, it is a chemical change, because there are bonds between the water and CuSO4. by heating, these bonds are broken, there is a color change not coming from the reactant.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
When copper sulfate pentahydrate is heated, the water molecules are driven off, leaving anhydrous copper sulfate as the solid residue. The chemical equation for this reaction is: CuSO4*5H2O(s) → CuSO4(s) + 5H2O(g).
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The blue copper sulfate pentahydrate loss by heating water and become an anhydrous white sulfate.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
The chemical equation for the dissolution of copper(II) sulfate pentahydrate in water is: CuSO4 5H2O (s) Cu2 (aq) SO42- (aq) 5H2O (l)
The reaction between silver (Ag) and copper sulfate (CuSO4) is a single displacement reaction. This is because the silver displaces the copper in the compound, resulting in the formation of silver sulfate and copper metal.
Calcium sulfate pentahydrate Source: Currently in chemistry and just finished covering a chapter with topics and subjects similar and equal to your question.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
To heat copper II sulfate pentahydrate, you would need to apply heat gradually to remove the water molecules bound in the crystal structure. As you heat it, the pentahydrate will lose its water molecules and eventually transform into anhydrous copper II sulfate, which is a white powder. It's essential to heat it gently to prevent decomposition or spattering.