No. Not really. It might work, but your engineering design margins would be slimmer than usual.
Probably...The 6V 40A relay figures out as 240Watts...The same relay at 12V 30A figures out as 360Watts.
The same as a 12V relay circuit, except it only needs 6V instead of 12V.
B8v (a) / k0iv (b) / a5v (c)
The peak-to-peak (P-P) value of a 6V square wave is the difference between its maximum and minimum voltage levels. For a square wave that oscillates between +3V and -3V, the peak-to-peak voltage would be 6V (3V - (-3V) = 6V). If the square wave oscillates between 0V and 6V, the peak-to-peak voltage would also be 6V (6V - 0V = 6V). Therefore, regardless of the specific levels, a 6V square wave has a peak-to-peak voltage of 6V.
It is: -10v+6v = -4v
0
yes, you can.
6 and 18v, respectively.
2u^2-6v-uv
5(6v + 7)(6v - 7)
The RELAY CIRCUIT used in electronics circuits for ,1. It is used for general mechanical SWITCH.2. It is used in High voltage switching mechanisms3. It is used in High voltage and current Applications.
IC 7806 is the voltage regulator that gives 6V dc voltage from 230V ac power supply. It is used to give power supply to the IC which operates on 6V.