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How acceleration occur in curve pattern?

Updated: 8/20/2019
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12y ago

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Net forces.

Consider a velocity - time graph for a person free falling from a plane.

Initially, on leaving the plane, the only force is due to the mass of the person under the effect of gravity, f = m * g (newtons) and effectively gives an initial acceleration of 1 g (about 10 ((m/s)/s)).

As soon as you are in motion however, air resistance will provide an opposing force (proportional to the square of the velocity), reducing the net force providing acceleration, so your velocity increase per second, will be diminished the faster you go.

Eventually the air resistance will match the force due to gravity at what is known as terminal velocity, where the net force is 0 and no further acceleration takes place.

:

Force down (constant) = mass * acceleration due to gravity.

Force up (varies with velocity) = velocity2 * drag coefficient.

The same reasoning can be applied to accelerating vehicles, except there are additional forces against due to rolling resistance.

an example graph form is v = 10t - t2, t from 0 to 5

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