Net forces.
Consider a velocity - time graph for a person free falling from a plane.
Initially, on leaving the plane, the only force is due to the mass of the person under the effect of gravity, f = m * g (newtons) and effectively gives an initial acceleration of 1 g (about 10 ((m/s)/s)).
As soon as you are in motion however, air resistance will provide an opposing force (proportional to the square of the velocity), reducing the net force providing acceleration, so your velocity increase per second, will be diminished the faster you go.
Eventually the air resistance will match the force due to gravity at what is known as terminal velocity, where the net force is 0 and no further acceleration takes place.
:
Force down (constant) = mass * acceleration due to gravity.
Force up (varies with velocity) = velocity2 * drag coefficient.
The same reasoning can be applied to accelerating vehicles, except there are additional forces against due to rolling resistance.
an example graph form is v = 10t - t2, t from 0 to 5
Calculate the gradient of the curve which will give the acceleration. Change the sign of the answer to convert acceleration into retardation.
The graph of velocity-time is the acceleration.
Actually, a car always accelerates on a curve. This is because acceleration, like the velocity it alters, is a vector that has both magnitude and direction. Since taking a curve involves a change of direction, there must be an acceleration to alter the direction; otherwise, the car can only continue straight.
If the vehicle is gaining speed on that gentle curve, yes. Otherwise, no.
that is acceleration at a particular point in time. If acceleration is changing with time, it is the slope of the velocity vs. time curve.
it measures the magnitude of acceleration, but it can't tell you the direction of the acceleration.
Only the acceleration brings a change in velocity.
The rate of Change in acceleration.
When demand curve intersects the supply curve.
An acceleration curve. Without knowing more details it's impossible to answer more precisely than that.
Since jerk is defined as the derivative (the rate of change) of acceleration, in the case of the area under the curve, it is the other way round: the integral (area under the curve) for jerk is the acceleration.
if its a velocity / time curve, it will show diminishing acceleration (slope of the curve) up to terminal velocity (forces balanced)