The formula is Kilowatts = I x E x 1.73 x pf/1000.
In exactly the same way as you do so for a single-phase load. It's the product of the power of the load, expressed in kilowatts, and the during of operation, expressed in hours. (And the symbol of kilowatt hours is 'kW.h', not 'kwh')
The amperage input of a transformer on a 208V three-phase system can be calculated using the formula: Amperage (A) = Power (Watts) / (Voltage (V) x √3). To determine the amperage, you need to know the power rating of the transformer in watts (or kilowatts). Once you have that, you can plug the values into the formula to find the input amperage.
Multiply the power of the load [1.732 x UL IL x power factor], expressed in kilowatts, by the operating time, expressed in hours. This is only practical for a constant load.
There are 1,000 kilowatts in a single megawatt. These are measures of electrical power which are based on the metric system.
The power factor is only taken into consideration when the Kilowatts of a transformer is used.
317.025280 KILOWATTS = 317,025.28 WATTS
To calculate kilovolt-amps (kVA) when kilowatts (kW) is known, you can use the formula: kVA = kW / power factor. The power factor is the ratio of real power (kW) to apparent power (kVA) in an electrical circuit.
The electrical engineering 3 phase is calculated by mathematics. The total active power is equivalent to three times the power of an individual phase.
3 phase system has more power than a single phase system
The Watt is the fundamental unit for power in the mks unit system of measurements. Kilowatts = 1000 Watts; so engine Kilowatts are the units used to measure the power of an engine. Truth be known, though. Kilowatts are more likely used for electric motors than they are for internal combustion engines. A common unit for engine power is horse-power (HP), but 1 HP = 746 Watts. So Watts can be used to measure engine power as well.
The power factor for a three phase generator is 80 percent. The generator consumes 36 kilowatts and a line to line voltage of 400 volts.
For a balanced load, you don't have to worry about phase values when you want to determine the power (or, in this case, the energy), whether delta or wye. Rather, you always use line values:P = 1.732 VL IL cos (phase angle)For an unbalanced load, however, you need to measure the phase voltage and phase current and power factor for each of the three phases, and add them together:P = [VpIp cos (phase angle)]phase A +[VpIpcos (phase angle)]phase B+[VpIp cos (phase angle)]phase CTo then calculate the energy expended in kilowatt hours, you need to multiply the total power (as calculated above), expressed in kilowatts, by the time for which the load is operating, expressed in hours.