The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.
is 3 phase Meter electicity to for the measurement of elektricity 3 phase.
Usually rating of CTs within 50- 80 percent. Of the maximum load current of the consumer does no change
A current transformer has to have the same ratio as the meter that it drives. Full scale deflection on the meter is 5 amps which equals the maximum allowed current on the phase that it is reading. A different ratio on the CT to meter would show an erroneous reading on the meter depending on the ratio of the connected CT. To keep costs down the meter is common to all three phases and is read by connecting the meter to the phase CT through a three position switch.
The method I have seen employed is to estimate the maximum current that will flow in the secondary side of the CT due to fault currents on the primary side, and calculate the total load (resistance) on the secondary side, including the CT resistance, cable resistance (2 way for ground faults, 1 way for three phase and L-L), resistance of any meters/relays connected to the CT. Once this is known, the voltage rise in the CT can be determined to see if the CT is likely to saturate.Alternately, you can determine the VA burden by the above, VA = V*I = (I*R)*I, using Ohm's law.The above answers the question of how to calculate the VA burdon on a current transformer. The VA burden of a CT is determined by the resistivity of the CT, multiplied by the current squared through the secondary. In general, this will be provided by the manufacturer in the form of a CT burden characteristic, developed through testing of the CT in question, not through calculations.
If, Ct value = 50 meter unit = 30 so, 50 x 30 = 1500 kwh
The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.
multiplying factor = Line CT Ratio / Meter CT Ratio Usually it is mentioned on Meter that MF = 1 if CT Ratio is 200/5 or MF = 2 if CT Ratio is 400/5. There can be an additional multiplication factor that would be mentioned on the meter.
CT/5 /number of turns=multiplier
The ratio would be a 50:1 current transformer.
mf is ratio of CT ration of meter box to CT ration written on meter. ex: CT meter box: 30/5, Meter ct ration 1/1. MF : (30/5)/(1/1)= 6
The ct ratio of the coil and multiplying it with the meter kwh reading.
It's given by f=ks, where k=2 and s=9
The measured Power in KWh will become one-third beacause the output of one CT which is reveresed will cancel the output of other CT and therefore the final output will be from only one CT (i.e 1/3 of total output)
Multiplication factor can be derived from Meter CT, Meter PT, Connected CT and Connected PT values.
The selection of CT Sizing is based on total connected load. If for example a Main CB of 2000 KVA Trafo is 4000 A -- then best selection would be 4000:5 -- this would match also in the Energy Meter (KWH Meter) with 800 as multiplier.
long travelling and cross travelling meter