First Step: Friedel Craft Acylation on benzene to form phenyl methyl ketone or acetophenone.
Second Step: Reduction of acetophenone by Clemmenen reduction using zinc amalgam and HCl to give the desired product. Another method is the reaction of benzene with ethyl chloride in presence of AlCl3 and heat in a close container.
not possible in a single step, but in four steps it is possible.
1-Dehydration of ethanol in presence of conc. sulphuric acid gives ethene.
2-Bromination of ethene with bromine water gives vicinal dibromide.
3-Dehydrohalogenation of vicinal dibromide with alcoholic KOH gives ethyne (acetylene).
4-When acetylene is heated in a sealed tube BENZENE is produced.
That is a very good question. But it is very hard to explain without the visualization of demonstration.
Oxidation (with KMnO4) then decarboxylation (with soda lime) of ethyl benzene gives methyl benzene (Toluene) the repetition of same processes with mthylbenzene gives the benzene.
The solubility difference between methyl alcohol (CH3OH) and benzene (C6H6) is related to the polar nature of methyl alcohol and the non polar nature of benzene. The OH group on methyl alcohol makes this a polar molecule and thus soluble in water. The lack of such a polar group in benzene makes it non polar, and thus insoluble in water.
The formula is C7H8.
benzene after oxidation convert into benzoic acid. zahra khan.
This group attached to benzene ring acts as the ortho-para directing group due to Hyperconjugation.
Benzene - a six carbon, six hydrogen [planar] ring - C6H6 - has no side-groups. Yet when any one single side-hydrogen is replaced with one Methyl (-CH3) Group, we have Toluene. Short Answer = one methyl group.
The solubility difference between methyl alcohol (CH3OH) and benzene (C6H6) is related to the polar nature of methyl alcohol and the non polar nature of benzene. The OH group on methyl alcohol makes this a polar molecule and thus soluble in water. The lack of such a polar group in benzene makes it non polar, and thus insoluble in water.
burr
The formula is C7H8.
Formula: C6H5CH3
benzene with 2~chloropropane in presence of aluminiumchloride
since benzene has a very less boiling point , it will evaporate easily if the mixture is heated . Thus we can obtain the vapour and condense it to obtain solid benzene
because change happens
toulene+sulphuric acid = o-methyl benzene sulphonic acid + p-methyl benzene sulphonic acid. Since methly group is ortho and para directed group so it activates benzene ring for electrophilic substitution reaction.
Some additives I know of Ethyl methyl lead (octane booster and upper cylinder lube) Methyl Benzene (octane booster)
benzene after oxidation convert into benzoic acid. zahra khan.
pH less than 7
This group attached to benzene ring acts as the ortho-para directing group due to Hyperconjugation.