Because gravitational potential energy is defined by g*m*h where g is the gravitational constant 9.8, m is mass, and h is height.
With just height and mass, you cannot calculate "wasted energy" by which i assume you mean energy lost to air resistance. However, if you are given the kinetic energy of the object just before it hits the ground, then you calculate the total energy before falling and compare it to the kinetic energy right before hitting the ground. the difference would represent the energy lost to air resistance
Kinetic energy of a falling object can be calculated for a specific height at a specific point since a falling body accelerates which means that it's velocity is changing every moment. To calculate the kinetic energy of a falling body at a certain height, we should know the mass of the body and its velocity at that point.Then we can apply the following formula: K.E. of an object = 1/2(mv2)
yes it does. u can calculate the final velocity of the falling object with the following eqn: initial potential energy= final kinetic energy or mgh = 1/2mv2 where m=mass, h = height,v=final velocity
2/ mass squared x height squared
The potential energy it had at height x when it was not moving is equal to the kinetic energy it will have as it is falling. Why? Law of the Conservation of Energy. Energy before will equal energy after.
If the object's falling energy increases (this would happen if the object is already falling downward, and air resistance is small), then the kinetic energy will increase.
Kinetic energy of a falling object can be calculated for a specific height at a specific point since a falling body accelerates which means that it's velocity is changing every moment. To calculate the kinetic energy of a falling body at a certain height, we should know the mass of the body and its velocity at that point.Then we can apply the following formula: K.E. of an object = 1/2(mv2)
yes it does. u can calculate the final velocity of the falling object with the following eqn: initial potential energy= final kinetic energy or mgh = 1/2mv2 where m=mass, h = height,v=final velocity
Mass of the object, height, and gravitational force. On Earth, Potential Energy = (mass) x (height) x (9.8 m/s)
A falling object.A falling object.A falling object.A falling object.
its mass and height
2/ mass squared x height squared
Because they are not mutually exclusive. Take for example a falling object; while falling at a given velocity it has (.5)(mass)(velocity)2=Kinetic Energy but also has the potential energy of whatever distance it has yet to fall, which equals (mass)(gravity)(height)=Potential Energy These two types of energy equal the Total Energy of the falling object, which never changes as it falls.
The potential energy it had at height x when it was not moving is equal to the kinetic energy it will have as it is falling. Why? Law of the Conservation of Energy. Energy before will equal energy after.
If the object's falling energy increases (this would happen if the object is already falling downward, and air resistance is small), then the kinetic energy will increase.
Energy related to the height of an object is gravitational potential energy.Energy related to the height of an object is gravitational potential energy.Energy related to the height of an object is gravitational potential energy.Energy related to the height of an object is gravitational potential energy.
When an object is lifted to a certain height, the mechanical energy of the person or system lifting the object gets transferred into the potential energy of the object. Thus if an object of mass/weight 'm' is lifted to a height 'h', then the potential energy possed by the object at height 'h' is given as: Potential Energy (P.E)= m*g*h, where g is acceleration due to gravity and whose value is 9.8 m/s2.
Height directly affects gravitational potential energy, since this energy is equal to mgh (mass x gravity x height). Height does not affect kinetic energy, which depends on the speed, not on the height. Except indirectly - for example, if an object is falling down, its speed will usually increase.