if u r talking about presuure drop then it can be easily calculate with the help of relation 4flv*v/2gd
in that f is the friction factor which is different for vraious type of flow for that u have to search a good book of fluid mechanics, v is the velocity. length of pipe and d is diameter of pipe
You need more information to perfom the calculation such as the fluid flow rate.
You would then divide the flowrate by the area get velocity.
Flow Rate Q= VA or V=Q/A. where q=flow rate, V= velocity, A=area.
p=row*g*h from it find out h,then v=sqareroot of 2gh then flow rate =area of c/s*velocity
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe
the velocity of water flow within a drainage pipe; the equation is V=L/t L= Length t=time. Then the flow rate; Fr=A*V, Where A= sectional area and V = velocity.
The Reynolds number, Re = VD/υ, can be used to measure the laminarity of flow. The smaller the Reynolds number, the more laminar the flow. Therefore, to achieve better laminar flow, V and D (velocity of fluid and diameter of pipe) should be small and υ, the kinematic viscosity of the fluid, should be large. Therefore, since pipe diameter and viscosity is fixed in this circumstance, the slower the velocity of the flow, the more laminar the flow. Open the faucet to a small degree and the flow will be laminar. Turn the facet open fully will (for some faucets) cause turbulent flow depending on the maximum velocity of water allowed by the faucet.
(to check the flow rate of water ... calculate the pressure drop
There are two factors which determine the flow rate of water. Diameter and velocity. Resistance is not needed for determining the size of waterlines to their respective flow rates. Resistance is a component of velocity calculated for determining several aspects such as pump hp, and loss of velocity over a distance. The formula without the resistance component is: Q=Av where: Q=Flow Rate A=Inside pipe area v=velocity Calculate: Q= (3.14XR squared)v lets assume a velocity of 10 inches per minute For 1/2 inch pipe: Q = (3.14 X 1/4" X 1/4")X10 inches per minute Q = 1.96 Cubic inches per minute For 3/4 inch pipe: Q= (3.14 X 3/8" 3/8") X10 inches per minute Q = 4.41 Cubic inches per minute So one 3/4 inch pipe will carry roughly 12% more water than two 1/2 inch pieces.
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe
Depends on the internal diameter, and the flow velocity. Velocity of water = Delta V Internal Radius= R RxRxV= Volume
That depends on what information is provided. If you don't have any information, you may actually need to measure the speed of the water; or you may want to measure the flow (for example, in liters per second), and the pipe diameter, and then calculate the speed from that.
I want to know based on flow and pressure how to calculate diameter of the pipe
The velocity of flow in any pipe is determined by three things. The internal pipe diameter, the mass flow rate of the liquid and the fluid density.
what is the discharge flow of 10m/s passing from 2ft pipe
Vapor pressure is the main factor in determining cavitation. Vapor pressure is a dependent on temperature. A pipes diameter becomes a main factor because it directly reflects the velocity of the pipe. Velocity is an important factor in determining cavitation in a pipe since it effects the velocity head for a piping system. If the velocity head is to great it could decrease the pressure inside of the pipe causing cavitation. Example: For a given pipethe flow will constant for. However the velocity in the pipe is dependent on its diameter. This is because velocity is based on the ratio of flow to area. Flow will not change but based on the diameter of the pipe it will have a different velocity. If the pipe had varying diameters the velocity will vary as well. Higher velocities will be at areas where the diameter is small and slower at areas where the diameter is larger.
Flow rate is diameter of hole*velocity, so the higher the velocity the higher the flow rate.
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Hi, For PSF we have to consider the velocity, For example: for Sewage Treatment it is 15m/hr and for Water Treatment it is 12m/hr. Calculation for Example: Flow rate : 10m3/hr Velocity : 12m/hr we have to use this formula: Area π/4 d2 = Flow rate/velocity π/4 d2 = 10/12 = 0.833 d2 = 0.833 * 4/π = 1.06 d = Sqrt (1.06) = 1.03m in mm = 1.03*1000 dia = 1030mm
Assuming that the pressure remains at a constant, reducing the diameter of the pipe will increase the water flow. On the contrary, increasing the diameter would cause the water to flow at a much slower rate.
the velocity of water flow within a drainage pipe; the equation is V=L/t L= Length t=time. Then the flow rate; Fr=A*V, Where A= sectional area and V = velocity.