There is no one line of code that can convert an array to a different type. A new String array would have to be created and values individually inserted into the array.
Example:
//Assume int[] i has been previously defined
String[] s = new String[i.length];
for(int i=0; i<s.length; i++)
s[i] = ""+i[i];
// assume we want to convert an int named some_int to a string
String s = Integer.toString(some_int);
That really depends on the programming language. In Java, it is sufficient to concatenate it with a String: int myNumber = 5; result = "" + myNumber; Other languages may require a special function, or method, to convert from integer to string.
I assume that your scanner is not scanning a string already, so if you are scanning an int then you can do: for the example you scanner variable is x .... x.intparseString();
Val() function is used in Visual Basic 6.0 to convert a string to a numeric value (such as integer, double etc.) or to extract a numeric value out of a string, as illustrated below.Val function as used to convert a string to a numeric valuefor example, let str be a string,Dim str as stringDim int as integerstr="09090"int=val(str)gives int = 9090also, used to extract the numeric part out of a following string,ie. a=val("98ASR_tyui") would give a=98however,b=val("The89")would give b=0 as there is no numeric value preceding the string.
There are different ways to do it. One is to convert it to a String, then use the string manipulations methods to extract individual digits as strings. You can then convert them back to numbers. Another is to do some calculations. For example, to get the last digit: int i = 12345; int lastdigit = i % 10; //To get additional digits, divide by 10 and repeat: i /= 10; int lastdigit = i % 10; In this case you can create a loop for this (repeating while i > 0), and copy the digits to an array.
You can perform arithmetic with it. int x {42}; x *= 2; // ok std::string s {"Hello"}; s *= 2; // error: std::string::operator*= (int) is undefined
One can convert a string variable to an int variable in Java using the parse integer command. The syntax is int foo = Integer.parseInt("1234"). This line will convert the string in the parenthesis into an integer.
int i= Convert.ToInt32("5");
To convert string to int in Java, the easiest way is to simply use the method Integer.parseInt(). For more information how to do this, refer to the integer class documents.
The same way you would in a regular java program. int i = 10; String s = i + ""; after the above line of code the variable s will have "10" as a string value...
Use the atoi() or atol() function.
int <integerName> = <integerValue>; String <StringName> = Integer.toString(<integerName>); /*where integerName is the name of the integer value, integerValue is the assigned value of the integer, and where StringName is the name of the string holding the parsed integer. */
That really depends on the programming language. In Java, it is sufficient to concatenate it with a String: int myNumber = 5; result = "" + myNumber; Other languages may require a special function, or method, to convert from integer to string.
I assume that your scanner is not scanning a string already, so if you are scanning an int then you can do: for the example you scanner variable is x .... x.intparseString();
lets say you have the following: Dim Int1 as Integer=12 Dim String1 as String 'Very Simple String1=Int1.tostring
Val() function is used in Visual Basic 6.0 to convert a string to a numeric value (such as integer, double etc.) or to extract a numeric value out of a string, as illustrated below.Val function as used to convert a string to a numeric valuefor example, let str be a string,Dim str as stringDim int as integerstr="09090"int=val(str)gives int = 9090also, used to extract the numeric part out of a following string,ie. a=val("98ASR_tyui") would give a=98however,b=val("The89")would give b=0 as there is no numeric value preceding the string.
int a; -- variable definition"int a" -- string literal
There are different ways to do it. One is to convert it to a String, then use the string manipulations methods to extract individual digits as strings. You can then convert them back to numbers. Another is to do some calculations. For example, to get the last digit: int i = 12345; int lastdigit = i % 10; //To get additional digits, divide by 10 and repeat: i /= 10; int lastdigit = i % 10; In this case you can create a loop for this (repeating while i > 0), and copy the digits to an array.