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If you'll take a look at its structure benzophenone is polar but during our laboratory we were able to determine if it's polar or non-polar by TLC. The TLC plate was developed in a mixture of petroleum ether and ethyl acetate with a 9:1 ratio respectively. This would mean that the solvent used is non-polar due to the large amount of petroleum ether. Finally our group was able to determine the Rf value of benzophenone and we found out that it has an Rf value of 0.4737 so this would mean that benzophenone is non-polar because its Rf value is near to 1.
benzophenone + NH3OHCl --> benzophenone oxime (+acid) ---> beckmann rearrangement --> benzanilide
Benzophenone is partially soluble in hexane. Benzophenone is polar, where as, hexane is nonpolar. "Like dissolves like."
diphenhydramine is preapred by reduction of benzophenone to benzhydrol , it then condensed with dimethyl amino ethyl chloride hydrochloride - Williamson's Ether synthesis to Diphenhydramine base , which converted in its hydrochloride salt .
From least to most polar: biphenyl >> benzophenone >> benzhydrol
The question here is asked in a slightly incorrect manner. Assuming I understand exactly what you meant to ask which is "In a reduction of Benzophenone is Diphenylmethanol created with a 1/1 molar ratio?" then the answer is yes they are. For every mole of benzophenone one mole of diphenylmethanol is created. Benzophenone is a reagent and diphenylmethanol is a product in a reduction of benzophenone reaction. However if you're referring to a reaction which creates BOTH diphenylmethanol and benzophenone as products, then you would need to provide the reagents that create the two.
The carbonyl group of the benzophenone acts as a hydrogen bond acceptor with the alcohol group of methanol.
Benzophenone prevents ultraviolet light from damaging colors and scents in products. Without the use of benzophenone some products would have to be shipped in black or dark packaging for protection.
HNO3= nitric acid
Lol, I am also from U of A and was having problem with that xD Anway, here's the solution I found First of all, you add ether and acid layers (In my case, the ether is 2-methoxy-2-methylpropane and my acid is 5%HCl). Ether layer help dissolve neutral napthlanene and acid helps dissolve ethyl 4-aminobenzoate. Now separate two layers. Keep in mind that aquaous layer contains 4-aminobenzoate in ionic form and organic layer contains naphthalene. You then add excess base (10%NaOH in my case) to aquaous layer because at this point aqueous layer contains ethyl 4-aminobenzoate in of of ethyl 4-aminobenzoatehydrochloride (The structure is very similar to ethyl 4-aminobenzoate, except that it has H+ and Cl- ions attached to the component of "NH2", which makes it "NH3+Cl-" at that component). Once the layer has turned basic, ethyl 4-aminobenzoate will be isoloated out.
Ether has a lower dielectric constant than water. Therefore, the energy required to separate the cations from the anions in ether is greater than in water. The entropy gain that could result from converting solid salt to a solution is therefore not great enough to overcome the attractions between the ions in ether, but it is great enough in water.
water.