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Q: How can you use 5 -Bit Adder as a Subtractor?
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Draw 8 bit half adder?

=HA#0-=FA#1-=FA#2-=FA#3-=FA#4-=FA#5-=FA#6-=FA#7=It consists of seven Full-Adder and one Half-Adder, has 2*8 input lines and 9 output line (8+carry).


Advantages of fast adder over parallel binary adder?

serial adder: 1) Slower 2) It uses shift registers 3) IT requires one full adder circuit. 4) It is sequential circuit. 5) Time required for addition depends on number of bits. Parallel adder: 1) Faster 2) It uses registers with parallel load capacity 3) No. of full adder circuit is equal to no. of bits in binary adder. 4)It is a combinational circuit 5)Time required does not depend on the number of bits


How do you convert 4b to 5b code in encoding techniques?

You will need to use this table to obtain the 5 Bit symbols.4-Bit 5-Bit Code0000 111100001 010010010 101000011 101010100 010100101 010110110 011100111 011111000 100101001 100111010 101101011 101111100 110101101 110111110 111001111 11101


4 bit combinational circuit decrementer using full adders?

Use the regular 4 bit full added, but make one of the inputs 1111 = 2's complimentrepresentation of -1. This will serve to decrement the other number by 1. Throw away the 5th bit, the carry bit. Example If 5 is entered: 0101 + 1111 ______ 0100 = 4 By -: lokesh kourav contact no -: 9201104655


I wanted the theory for implementation of full adder using 3 to 8 decoder and 4 input nand gates?

A full adder is a logic circuit that take two inputs and a carry input, and produces an output and a carry ouput. It is one stage in a multi-bit adder. The truth table is: ABC RC D000 00 0001 10 1010 10 2011 01 3100 10 4101 01 5110 01 6111 11 7The columns are A, B, Carry Input, Result, Carry Output, and Decoder Output You can use a 3 to 8 decoder to generate these 8 lines. Look at the R and C outputs, and note that there are 4 combinations of inputs thet generate a 1 or a 0. For each of Result and Carry Ouput, connect the decoder output representing the 0 state to those four lines. (Result = 0, 3, 5, 6. Carry Output = 0, 1, 2, 4) What you are doing logically is or'ing the lines to produce the 1's. Since you have nands instead or ors, treat the nands as nors and pick the opposite inputs.