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Determining density of an irregular objectDensity is mass per unit volume, so if you know an object's mass and the space it occupies, then you can calculate its density.

If you had a scale, you could weigh the object to determine its mass. (Note that mass is not the same as weight, but the two are closely related insofar as we use weight to determine mass.) You could then carefully submerge it completely in water to determine how much water it displaced. That would tell you its volume. You would then divide the mass by the volume to get its density.

But what if you don't have a scale? Can you still determine its density? I think you can.

Place a known quantity of water in a graduated container. Carefully place the object in the container and note the change in the water level. Subtract the new water level form the old. That is the amount of water displaced by the object, which should be floating since it's less dense than the water. The weight of the water displaced by the object is equal to the buoyant force pushing up on the object.

What does this tell us? Well, since the object floats, we know that the buoyant force is equal (but opposite) to the weight of the object. In other words, if we know the magnitude of the buoyant force, we know the object's weight (and therefore its mass)! Now, you can divide its mass by its volume, which you determined earlier by fully submerging it.

Here's another wayDetermine how much water is displaced by the floating object. Then carefully fully submerge the object and record how much water is displaced. If you divide the first number by the second, you will know its relative density compared to the density of water!

If the floating object displaces 100 ml of water and the fully submerged object displaces 150 ml, then the relative density is 100/150 = 0.667. Since the density of water is 1.00 g/cm3, that means the density of the object is 0.667 g/cm3.

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Bennett Bode

Lvl 13
2y ago

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Related Questions

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