Use an ammeter connected in series with the supply.
Make sure the ammeter is of sufficient size to cope with the maximum current.
Add up all the wattages of devices used (stamped on them) to get a clue as to how much it may take. Divide the wattage by 12v to get Amps.
On a vehicle, do not crank the engine with the ammeter attached to the battery. Unless the ammeter can stand several hundred amps. (Unlikely)
0.24 ampere
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt lightbulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt powersource and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. Regards.
Given R=? I=12 ampere V=120 Volts equation I=V divided R Solution; R=12 ampere 120 Volts answer (10)
can ou step down 36 volts dc to 12 volt dc using batteries
Batteries are generally not listed as having watts. And there are a couple of different ampere ratings. But if you're running something needing 12W of a 12V battery it's pulling 1A out of the battery at the moment.
The 5 amp fuse has many wattages that it can protect. It depends on the voltage of the circuit that the fuse is protecting. Use the following formula, Watts = Volts x Amps. For example 120 volts x 5 amps = 600 watts, 240 volts x 5 amps = 1200 watts, 480 volts x 5 amps = 2400 watts and 600 volts x 5 amps = 3000 watts.
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If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt light bulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. In simpler words: If you double the bulbs, twice the current is drained from the battery
A 120V household electrical outlet supplies 12 watts of powerwhen the current is 0.1 Ampere (and the power factor is 100%).
The same number as 250 oranges is apples. A watt is a volt times an ampere.
Power = voltage x currentCurrent = power/voltage = 12/120 = 0.1 ampere = 100 milliamperes
The outlet is rated for 30A, so anything up to, but not exceeding 30A can be plugged in.