If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator.
12 Volt and One 12 Watt lightbulb drains 1 Ampere Current.
12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current.
However:
If having a 24 volt powersource and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current.
NOTE:
Wattage and Voltage of bulbs may be different even if the sockets are the same.
Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second.
It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for.
Total Current/Ampere= Combined Wattage divided by Voltage
Total Wattage = Combined Current or Ampere multiplied by Voltage.
Regards.
It is halved. coz voltage=current * resistance
When the voltage in a circuit is doubled, the current typically increases, assuming the resistance remains constant according to Ohm's Law (V = IR). If resistance is unchanged, doubling the voltage will result in doubling the current. However, if the circuit components have nonlinear characteristics, the actual change in current may vary. Always consider the specific characteristics of the circuit for precise outcomes.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
If resistance is halved while voltage remains constant, the current will double.
It is halved. coz voltage=current * resistance
If resistance is doubled in a circuit with constant voltage, Ohm's Law (V=IR) states that current (I) would be halved since the voltage is constant. This is because the relationship between resistance and current is inversely proportional.
If the voltage in a circuit were doubled, the current would also double according to Ohm's Law (I = V/R), assuming the resistance in the circuit remains constant. This is because current is directly proportional to voltage when resistance is held constant.
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
When the voltage in a circuit is doubled, the current typically increases, assuming the resistance remains constant according to Ohm's Law (V = IR). If resistance is unchanged, doubling the voltage will result in doubling the current. However, if the circuit components have nonlinear characteristics, the actual change in current may vary. Always consider the specific characteristics of the circuit for precise outcomes.
In a parallel circuit, the total resistance remains the same when the voltage applied is doubled. Each branch in the parallel circuit will experience the same increase in voltage, but their individual resistances will remain constant.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
If the voltage is doubled and the resistance is constant, Ohm's Law states that the current will also double. This is because the relationship between voltage, current, and resistance is linear, and increasing the voltage will directly increase the current flow.
If the potential difference across a circuit is doubled, the current flowing through the circuit will also double, assuming the resistance remains constant. This is because Ohm's Law states that current is directly proportional to voltage when resistance is held constant.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
Inversely. As resistance increases, current dereases; given that the applied voltage is constant.