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How do initial velocity affect range and height of a projectile?
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What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
An object projected up with initial velocity v attains a height h Another object projected up with initial velocity 2v will attain what height?
4h
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
What is the initial arclength of a pendulum when you know the length and mass and max velocity and initial height of the pendulum?
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
An object projected up with initial velocity v attains a height h Another object projected up with initial velocity 2v will attain what height?
4h
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
Why projectile angle increase when projectile range also increase?
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
What is the initial arclength of a pendulum when you know the length and mass and max velocity and initial height of the pendulum?
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
initial velocity of the kick = 28.06 m/s
. ok v velocity a acceleration but what about you?
if by 'you', you mean 'u' then u is the initial velocity v is the final velocity. you need to know the initial velocity in trajectory question (motion of an object through the air) to find height, acceleration, time etc.
How do you find the firing angle for a projectile given the targets x and y coordinates and initial velocity I would like to do it without calculus if possible.?
They height y of the projectile is given by the function y = vosin(0)t + 1/2gt2, where vo is the initial velocity of the projectile, 0 is the firing angle, t is the time, and g is the acceleration of gravity (-9.81m/s2). The range x of the projectile is given by the function x = vocos(0)t. Rearranging this last equation for time yeilds t = x/(vocos(0)); this will give us the length of time the projectile takes to reach the target. Substituting this into the first equation yeilds: y = vosin(0)[x/(vocos(0))] + 1/2g[x/(vocos(0))]2 this can be simplified further but it is not necessary to do so; plugging it the x and y coordinates, the initial velocity, and the acceleration of gravity, you should be able to solve for 0, which is now the only unknown.
