Throw it with zero horizontal speed, i.e. straight up.
(Remember to move out of the way.)
If the projectile's velocity has a horizontal component - in other words, it doesn't go straight up - then its speed will never be zero.
Zero.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
The vertical velocity is 0. The horizontal velocity is constant during the entire trajectory (and may be zero).
No, assuming no air resistance, there will be a constant downward acceleration of 9.8 meters per second square (assuming standard gravity). The vertical component of the velocity will be zero at the top of the trajectory.
If the projectile's velocity has a horizontal component - in other words, it doesn't go straight up - then its speed will never be zero.
Zero.
A projectile has minimum speed at the top of the trajectory.
The projectile have minimum speed when it is in top of prabolic and it have max sped when it is in intial point
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
Yep that is correct. To understand this it may help you to draw a parabola. If you draw a line from the top of the parabola back to the ground you'd notice either side of this line is symmetrical. This isn't quite what happens to a projectile (following a parabolic path), but because of the nature of the question, effects such as air resistance can be ignored. As the projectile approaches the top of its path, the vertical component of its velocity approaches zero. As the projectile begins to fall the magnitude of the vertical component of the projectile begins to increase. The only force that acts on the projectile during flight is gravity which pulls it towards the earth. Since this force and the horizontal component of the projectiles velocity are at right angles to each other, the horizontal component of the velocity is unaffected during flight . This explains the symmetry of the parabola and also means the time to reach the top of path equals the time from the top of path back to the ground. The projectile will hit the ground with the same speed as it left the ground. If you draw a horizontal line through the parabola, at the two points where the line and the parabola cross, the speed of the projectile will be the same. The only change to the balls speed during the flight comes as the vertical component of its velocity tends to zero as it reaches the top of the curve and then falling back down due to gravity. I'm unsure of your physics knowledge but hopefully this doesn't confuse you. If you have learned about vectors, then this can be simply understood/explained.
Acceleration at the point of zero vertical velocity will be equivalent to gravitational acceleration on that body. On Earth, for example, this is around 9.8 meters per second per second (9.8m/s2).
The vertical velocity is 0. The horizontal velocity is constant during the entire trajectory (and may be zero).
No, assuming no air resistance, there will be a constant downward acceleration of 9.8 meters per second square (assuming standard gravity). The vertical component of the velocity will be zero at the top of the trajectory.
The 2007 Toyota Camry has a top speed. The Toyota Camry can go from zero to sixty miles in 6.8 seconds. Its top speed is 145 miles per hour. This is the top speed of the Toyota Camry.
At the top of the jump, your speed is changing from upward to downward speed, so there's an instant there where your speed is zero. -- Potential energy is max, because your height is max. -- Kinetic energy is zero, because your speed is zero.
At the top of the path, the projectile stops rising and starts falling. The vertical component of velocity at that point is zero.