As soon as you can say/spell deoxyribonucleic acid maybe someone will help you
Investigators may spray a crime scene with hydrochloric acid (HCl) before using luminol to help remove any potential contaminants or residues that could interfere with the reaction of luminol with blood. This ensures a clean surface for the luminol to detect any hidden blood traces effectively.
To effectively solve polyprotic acid problems, one should first identify the number of acidic hydrogen atoms in the acid. Then, calculate the equilibrium concentrations of each protonated form of the acid using the acid dissociation constants (Ka values). Finally, use the mass balance and charge balance equations to determine the concentrations of all species in the solution.
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You can use the formula M1V1 = M2V2 to solve the problem. Given that M1 = 15M, V1 = unknown, M2 = 1.7M, and V2 = 300mL, you can rearrange the formula to solve for V1. The volume of 15M Nitric acid required to make 300mL of 1.7M Nitric acid is approximately 10.6mL.
Because events in either country can cause acid rain to drift over the other.
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It can be. It depends on what you vandalize. For example: It IS a federal crime to vandalize a reproductive health care facility by gluing locks or pouring butyric acid.
For a weak acid, HA...HA ==> H^+ + A^- Ka = [H+][A-]/[HA] Plug these values into the Ka equation. You also must know the [HA] that you start with. Solve for [H+] Take -log [H+] = pH
To effectively solve buffer problems, one should first identify the components of the buffer solution (acid and conjugate base), calculate the initial concentrations, and use the Henderson-Hasselbalch equation to determine the pH. Adjusting the ratio of acid to conjugate base or adding more buffer solution can help maintain a stable pH.
The equation is acid + water equalizes into hydronium and conjugate base, and Ka (acid dissociation constant) is products divided by reactants. If the Acid = (H+)(base)/Ka, then the acid concentration is (H+)(H+)/Ka, or (0.0001)(0.0001)/0.0000001, which equals 1M.
13.5 gallonsThe 50% acid solution will contain 4.5 gallons of acid & 4.5 gallons of water.So let X be the number of gallons of pure acid to add. You can set up an equation to solve for X:(4.5 + X )------------- = 0.80 (80% solution)(9 + X)The top part of the fraction is the amount of acid in the new 80% solution & the bottom part will be the total amount of solution you have. Cross multiply and solve for x.(9+X)*(0.80) = (4.5+X)*(1)7.2 + 0.8X = 4.5 + X7.2 - 4.5 = 1X - 0.8X2.7 = 0.2XX = 2.7/0.2 = 13.5
The acid dissociation constant (Ka) is the measure of strength of an acid in solution. Symbolically, as HA is added to solution it breaks down into a proton (H+) and it's conjugate base (A-). The value of Ka is equal to products over reactants (aqueous only i.e. no solids or liquids) . Once you solve for Ka, you can solve for the pKa which is equal to -logKa. The pKa will determine if the acid is weak or strong. Strong acids are more willing to dissociate in water and have a pKa value of <-2. The pKa of ascorbic acid is only 4.2, and so it is a weak acid.