Oxygen diffuses 1.4 times as fast as sulfur dioxide.
The rate of diffusion is inversely proportional to the square root of the molar mass of the gas. Since sulfur dioxide has a molar mass twice that of oxygen, it will diffuse at a slower rate compared to oxygen.
No, oxygen, hydrogen, and carbon dioxide do not weigh the same. They have different atomic masses, with oxygen being heavier than hydrogen and carbon dioxide being heavier than both oxygen and hydrogen.
Helium will diffuse faster than sulfur dioxide. This is because helium is lighter than sulfur dioxide, so it will move faster through a given medium due to its lower molar mass and therefore higher average speed of molecules.
This type of analysis would fall under the study of stoichiometry in chemistry. By examining the chemical formula of sulfur dioxide (SO2), you can determine the number of sulfur and oxygen atoms, and subsequently calculate their masses and number of moles based on the molar mass of sulfur and oxygen.
This is the law om mass conservation.
This is the law om mass conservation.
To calculate the percentage of oxygen in carbon dioxide, you can use the molar masses of carbon and oxygen. The molar mass of carbon dioxide is 44 g/mol (with 32 g/mol from O2 and 12 g/mol from C), and the molar mass of oxygen is 32 g/mol. Therefore, the percentage of oxygen in carbon dioxide is (32 g/mol / 44 g/mol) * 100 = 72.7%.
Only if you included the Oxygen produced as well.
Carbon is a metal element. Atomic mass number of it is 12.
The formula mass of carbon dioxide (CO2) can be calculated by adding the atomic masses of carbon and two oxygen atoms. The atomic mass of carbon is 12.01 u, and oxygen is 16.00 u. Thus, the total formula mass of carbon dioxide is approximately 44.01 u.
A compound with 50% sulfur and 50% oxygen would be sulfur dioxide (SO2). It is a colorless gas with a pungent odor and is commonly produced from the burning of sulfur-containing compounds. SO2 is known for its role in air pollution and acid rain formation.
It is used to compare masses.