carbon dioxide contains about 27.27% carbon.
27.3
The equation for the reaction is C + O2 -> CO2. The relevant gram atomic masses are 12.011 for carbon and 15.9994 for oxygen. Therefore, the ratio of the mass of carbon dioxide produced to carbon burnt is [2(15.9994) + 12.011]/12.011 or about 3.66. From burning 3 grams of carbon, the mass of carbon dioxide produced is therefore 1 X 101 grams, to the justified number of significant digits.
44.010 g/mol You can sum up atomic weight of 1 carbon and 2 oxygen to this figure.
The gram molecular mass of carbon dioxide is about 44.01 grams. By definition, this value is the number of grams of carbon dioxide that contains Avogadro's Number ("AN") of molecules. Avogadro's Number is about 6.022 X 10^23. Therefore the number of molecules in 1 gram is (1/44.01)(AN) or 2 X 10^21 molecules, to the justified number of significant digits.
carbon dioxide contains about 27.27% carbon.
When methane burns, the carbon dioxide and water formed, equal the mass of the methane plus the mass of the oxygen.
The gram molecular mass of hexane is 86.18. Therefore, 25.0 g of hexane constitute 25.0/86.18 or 0.290 moles. Each mole of hexane contains six carbon atoms and therefore will produce six molecules of carbon dioxide by burning in an excess of oxygen. 6 X 0.290 = 1.74 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.00. Therefore, the mass of carbon dioxide produced will be 1.74 X 44.00 or 76.6 grams of carbon dioxide, to the justified number of significant digits.
44.0095 amu
Carbon dioxide's chemical formulae is CO2, and waters chemical formulae is H2O. If you look at the periodic table you will find a number called the mass number. This is the mass of that particular element. To find the mass of a compound such as carbon dioxide or water you simple add up the mass numbers of each individual element within that compound. So for CO2 you add 12(for carbon,C) and 16(for oxygen,O) and again another 16 (for the 2nd oxygen) you get 44 for the total mass of carbon dioxide. If you now do the same for water adding 1, 1 and 16 you get a total mass number of 18. 44 is higher than 18 therefore carbon dioxide is the heavier compound
First: Carbon (not carobon) dioxide is a compound, CO2, thus a molecule, not an atom.Second: Its molecular mass (not atomic mass number) is the sum of the atomic mass of carbon (C), which is 12.01 u, plus 2 times the atomic mass of oxygen (O), which is 2 x 16.00 = 32.00 u.All together this is 44.01 u, meaning thatone mole of carbon dioxide weights 44.01 gram
First of all, carbon dioxide is a molecule and hence the question should be: What is the molecular mass of carbon dioxide? and the answer is 12 + (2 x 16) = 48
The molar mass of sodium acetate is 82,03. The molar mass of carbon dioxide is 44,01.
44.0095 amu
44.0095 amu
27.3
The equation for the reaction is C + O2 -> CO2. The relevant gram atomic masses are 12.011 for carbon and 15.9994 for oxygen. Therefore, the ratio of the mass of carbon dioxide produced to carbon burnt is [2(15.9994) + 12.011]/12.011 or about 3.66. From burning 3 grams of carbon, the mass of carbon dioxide produced is therefore 1 X 101 grams, to the justified number of significant digits.