Not possible. Of course you can call a function which does the addition for you, but function-calling is also an operator in C.
Add two numbers.
By using repeated addition. Consider two numbers a and b. If you want to find a*b then you can add the numbers repeatedly in a loop to get the product. Eg:product = a;for( i=1; i
Not possible. Let's not forget than in C the followings are all operators:+, -+=, -=++, --=&, *, []function-call
If you simply add numbers the answer is the sum of those numbers.
int main() { int a=10,b=20; while(a--) b++; printf("%d",b); } or: a -= -b;
Using the additive property (+).
The best method is to add the numbers, using arithmetic.
you ADD all the #s
Operator overloading allows c/c++ operators to have user defined meanings on user defined types. For example + operator is used to add to numbers but we can also use it for concatenating a string the only limitation is you cannot change the literal meaning of the operator.
add them all together and then divide the answer by the number of numbers.
You can make use of pointers to achieve this.void add( int *a, int *b){(*a) += (*b);}Now if two numbers a and b are given and you need to store the value in variable c, then you would perform:c = a;add(&c,&b);
first add the whole numbers then do simple fraction subtraction