At a very simplistic level.
Take iron chloride
When it is FeCl2 , then iron is in oxidation state '2'
When it is FeCl3 ; then iron is oxidation state '3'.
However, for more complex molecules like potassium permanganate. The formula is KMnO4 . What is the oxidation state of the manganese (Mn)
First of all the'K' is in oxidation state of '1' because it is a Group '1' metal .#So the manganate ion is MnO4^-
As a standard , use oxygen at '-2'
Since we have 4 x oxygen the oxygen moiety is 4 X -2 = -8
We note that the ionic charge is '-1'
So creating a sum
-8 + Mn = -1
We have
Mn = 8 - 1 = (+)7
So the manganese is in oxidation state '7'
Oxidation number is the number of electrons in the pouter energy shell involved in the bonding process. Not all electrons in the outer energy shell are involved in the bonding process. e.g. Water has two lone pairs (4 electrons) , in the outer energy shell, not involved with bonding with the hydrogen atoms.
.
-1 for Cl and +4 for Ti
It can mean that the element has lost 2 electrons to form a pos. 2 ion. Or it can mean that in a particular compound (or polyatomic ion) that atom is combined with more electronegative elements in a particular combination that the rules used to assign oxidation numbers gives this atom a +2 oxidation number.
I think that Pb is +2 and I is -1. Mrs. Anderson
It is customary to assign oxygen an oxidation number of -2, except in peroxides and superoxides. Using this convention, phosphorus must have an oxidation number of +3 to balance the charges in P4O6. (6 X 2 = 4 X 3)
Oxidation numbers are an invention of chemists; they are simply an accounting scheme that helps chemists to keep track of things in a redox reaction. There are several different ways to assign oxidation numbers in ozone. The only fixed point that all would agree on is that the sum of oxidation numbers on the three atoms must come to zero. Argument 1: All 3 atoms are oxygen, so they all have the same electronegativity, so the oxidation numbers must be 0,0, and 0 Argument 2: When writing the formula of ozone and trying to obey the rules of valence, you have to use formal charge. The formula could be written O=O(+)-O(-) In this case the oxidation numbers must be assigned as 0,+1, and -1 Argument 3: The formulation of argument 2 is correct BUT both "end" oxygen atoms are in symmetrically identical environments, and the formula written above is just one of two resonance structures. The symmetry of the molecule must be recognised, and so the oxidation numbers are -1/2 , +1, and -1/2 You can find professional chemists who will argue quite strongly for any one of these three assignments. None of them is really "right" or "wrong". It is all a matter of how you want to do your accounting. (But just sit back and nod wisely if you find a chemist who is arguing passionately for a particular assignment).
-1 for Cl and +4 for Ti
It can mean that the element has lost 2 electrons to form a pos. 2 ion. Or it can mean that in a particular compound (or polyatomic ion) that atom is combined with more electronegative elements in a particular combination that the rules used to assign oxidation numbers gives this atom a +2 oxidation number.
I think that Pb is +2 and I is -1. Mrs. Anderson
Any numbers you care to assign to them.
These are the rules of assigning oxidation numbers in compounds (in order of priority): 1. All group 1 metals have an ON of +1 2. Group 2 metals have an ON +2 3. Al is in group 3 and so has an ON of +3 4. O has an ON of -2 (except in peroxides where it is -1) 5. H has an ON of +1 (except in metal hydrides where it is -1) 6. F has an ON of -1 7. Cl has an ON of -1 except in compounds with O and F Therefore, to assign C a oxidation number you have to work out the rest first as all the oxidation numbers in the compound have to make 0. Mg has a ON of +2. (rule 2) O has an ON of -2 (rule 4) but there are 3 O's and so you have to do 3x-2 = -6 Therefore, you have -6 (O) + 2 (Mg) = -4 Therefore, the ON of C must be +4 to make it equal to 0. Oxidation numbers of the individual elements: Mg C O3 +2 +4 -2
Yes the N numbers you see are assigned by the FAA.
Phone companies assign phone numbers arbitrarily; there is no formula.
assign to green, yellow, and red areas.
by the lot tracking software...
There were earthquakes before there were people around to assign numbers to a year.
It is customary to assign oxygen an oxidation number of -2, except in peroxides and superoxides. Using this convention, phosphorus must have an oxidation number of +3 to balance the charges in P4O6. (6 X 2 = 4 X 3)
Oxidation numbers are an invention of chemists; they are simply an accounting scheme that helps chemists to keep track of things in a redox reaction. There are several different ways to assign oxidation numbers in ozone. The only fixed point that all would agree on is that the sum of oxidation numbers on the three atoms must come to zero. Argument 1: All 3 atoms are oxygen, so they all have the same electronegativity, so the oxidation numbers must be 0,0, and 0 Argument 2: When writing the formula of ozone and trying to obey the rules of valence, you have to use formal charge. The formula could be written O=O(+)-O(-) In this case the oxidation numbers must be assigned as 0,+1, and -1 Argument 3: The formulation of argument 2 is correct BUT both "end" oxygen atoms are in symmetrically identical environments, and the formula written above is just one of two resonance structures. The symmetry of the molecule must be recognised, and so the oxidation numbers are -1/2 , +1, and -1/2 You can find professional chemists who will argue quite strongly for any one of these three assignments. None of them is really "right" or "wrong". It is all a matter of how you want to do your accounting. (But just sit back and nod wisely if you find a chemist who is arguing passionately for a particular assignment).