First balance Carbon (add 4 at right side, 4=4)
C4H10 --> 4 CO2 + H2O
Then balance Hydrogen (add 5 at right side, 10=5*2 )
C4H10 --> 4 CO2 + 5 H2O
Then balance Oxygen (add 6.5 O2 at left side, (4*2 + 5)right = 13 = (6.5*2)left
C4H10 + 6.5 O2 --> 4 CO2 + 5 H2O
Multply both siide by 2 to prevent halved quantities
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
There is no way to balance that, because no matter how you group the molecules you're either creating oxygen atoms or destroying hydrogen atoms.We can fix that problem by assuming there's also oxygen present as a reactant and the water and carbon dioxide are products.
This is an extremely simple equation to balance, by the way, you should be able to do it trivially by accounting for the carbon and hydrogen and then working out how much oxygen you need.
Each butane (C4H10) has 4 carbon atoms, and will produce four CO2 molecules (using four O2 molecules to do so).
Each butane has 10 hydrogen atoms, and will produce five H2O molecules, using ... er ... okay, it's a LITTLE more complicated ... two and a half O2 molecules to do so. To fix this "half molecule" problem, we just multiply everything by two, and come up with
2 C4H10 + 13 O2 -> 10 H2O + 8 CO2
Checking, that's 2x4 = 8 carbon on the left and 8x1 = 8 carbon on the right, so that's good.
Hydrogen: 2 x 10 = 20 and 10 x 2 = 20 ... also good.
Oxygen: 13 x 2 = 26 and (10 x 1 = 10 plus 8 x 2 = 16) = 26.
Everything balances, so that must be the right equation.
The balanced chemical equation for the combustion of ethane (C2H6) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is:
C2H6 + 7O2 -> 2CO2 + 3H2O
the balanced equation is 2_C7H6O2+15_O2-->14_CO2+6_H2O
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
Every thing balanced first but O2. Leave that for last.
2C2H6 + 7O2 -> 4CO2 + 6H2O
Watch the carbohydrate and balance oxygen last.
(C4H10O)l + 6(O2)g = 4(CO2)g + 5(H2O)l
c3h6+o2---co2+h2o
2c2h6 + 7o2 -> 4co2 + 6h2o
2C2H6 + 7O2 -> 4CO2 + 6H2O
The balanced equation for the reaction between C2H6 (ethane) and O2 (oxygen) is: 2C2H6 + 7O2 --> 4CO2 + 6H2O
The covalent name of C2H6 is ethane.
'c' C2H6 ( Ethane) The others are INORGANIC Molecules. Remember , organic chemicstry deals with the chemistry or CARBON compounds. If no carbon is present then it is INORGANIC.
The balanced chemical equation for the reaction C2H2 + H2 → C2H6 is: C2H2 + 2H2 → C2H6
The balanced chemical equation for the reaction between C2H5OH (ethanol) and H2O (water) is: C2H5OH + H2O → CH3COOH + H2 This reaction produces acetic acid (CH3COOH) and hydrogen gas (H2) as products.
This chemical equation is unbalanced. To balance it, start by balancing the carbons, then hydrogens, and finally oxygens. The balanced equation is: C4H10 + 6.5 O2 -> 4 CO2 + 5 H2O.
C2H5MgBr + H2 = C2H6 + MgBr2
2C2H6 + 7O2 --> 4CO2 + 6H2O
The balanced equation for the reaction between C2H6 (ethane) and O2 (oxygen) is: 2C2H6 + 7O2 --> 4CO2 + 6H2O
The balanced chemical equation for that reaction is: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
The balanced chemical equation for the reaction between C2H5OH (ethanol) and H2O (water) is: C2H5OH + H2O → CH3COOH + H2 This reaction produces acetic acid (CH3COOH) and hydrogen gas (H2) as products.
The reactants are C8H18 and oxygen.
Compound c, C2H6, is a hydrocarbon. It consists of only carbon and hydrogen atoms, which are the defining characteristic of hydrocarbons. The other compounds listed contain oxygen in addition to carbon and hydrogen.
1molecule of C2H6 contains 2 carbon atoms
The molecule C2H6, also known as ethane, is commonly used as a fuel for heating and cooking. It is also used as a precursor in the production of ethylene, a key raw material for plastics manufacturing. Additionally, ethane is used in the petrochemical industry for various processes such as ethylene cracking.
After the ignition of the mixture, all of the C2H6 (2 moles) will react with O2. The limiting reactant is O2 since it is not in stoichiometrically balanced proportions with C2H6. Thus, all 1.6 moles of O2 will react completely, and some of the C2H6 will be left unreacted.
a) NH3: ammonia has a net dipole moment due to the unequal sharing of electrons between nitrogen and hydrogen. b) C2H6: ethane has no net dipole moment because the carbon-carbon and carbon-hydrogen bonds cancel out each other's dipole moments. c) PBr3: phosphorus tribromide has no net dipole moment because the dipole moments of the three P-Br bonds cancel each other out. d) SiO2: silicon dioxide has no net dipole moment due to its symmetrical arrangement of silicon and oxygen atoms.