First balance Carbon (add 4 at right side, 4=4)
C4H10 --> 4 CO2 + H2O
Then balance Hydrogen (add 5 at right side, 10=5*2 )
C4H10 --> 4 CO2 + 5 H2O
Then balance Oxygen (add 6.5 O2 at left side, (4*2 + 5)right = 13 = (6.5*2)left
C4H10 + 6.5 O2 --> 4 CO2 + 5 H2O
Multply both siide by 2 to prevent halved quantities
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
This equation can not be balanced with the species present. Are you sure the species are correctly written?
The covalent name of C2H6 is ethane.
'c' C2H6 ( Ethane) The others are INORGANIC Molecules. Remember , organic chemicstry deals with the chemistry or CARBON compounds. If no carbon is present then it is INORGANIC.
The balanced chemical equation for the reaction C2H2 + H2 → C2H6 is: C2H2 + 2H2 → C2H6
To find the mass of carbon in C2H6, we first need to calculate the molar mass of C2H6. Carbon has a molar mass of 12 g/mol, and hydrogen has a molar mass of 1 g/mol. The molar mass of C2H6 is (212) + (61) = 30 g/mol. The mass of carbon in 350 grams of C2H6 is then (2*12)/30 * 350 = 140 grams.
C2H5MgBr + H2 = C2H6 + MgBr2
2C2H6 + 7O2 --> 4CO2 + 6H2O
2c4h10o + 13o2 -----> 8co2 + 10h2o
You mean balance it? 2C2H6 + 7O2 -> 4CO2 + 6H2O
This equation can not be balanced with the species present. Are you sure the species are correctly written?
The reactants are C8H18 and oxygen.
The covalent name of C2H6 is ethane.
1molecule of C2H6 contains 2 carbon atoms
'c' C2H6 ( Ethane) The others are INORGANIC Molecules. Remember , organic chemicstry deals with the chemistry or CARBON compounds. If no carbon is present then it is INORGANIC.
Balanced equation first. 2C2H6 + 7O2 -> 4CO2 +6H2O I suspect C2H6 of limiting the reaction. 2 moles C2H6 (1.6 moles O2/2 moles C2H6) = 1.6 moles O2 left over and all of the C2H6 is consumed.
The balanced chemical equation for the reaction C2H2 + H2 → C2H6 is: C2H2 + 2H2 → C2H6
C2h6