350 g C2H6 x 1 mole C2H6/30 g x 2 moles C/mole C2H6 x 12 g/mole C = 280 g carbonDone another way:
%C = 24/30 (x100%) = 80%
0.8 x 350 g = 280 grams carbon
To find the number of carbon atoms in 77.28g of ethane (C₂H₆), first calculate the number of moles of ethane by dividing the mass by its molar mass (30.07 g/mol). Then, since each molecule of ethane contains 2 carbon atoms, multiply the number of moles by Avogadro's number (6.022 x 10²³) to find the number of carbon atoms.
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
moles = mass/relative atomic mass 1 = mass/12 mass = 12 x 1 = 12 grams
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
The mass of carbon in carbon dioxide is 12 grams per mole.
To find the number of carbon atoms in 77.28g of ethane (C₂H₆), first calculate the number of moles of ethane by dividing the mass by its molar mass (30.07 g/mol). Then, since each molecule of ethane contains 2 carbon atoms, multiply the number of moles by Avogadro's number (6.022 x 10²³) to find the number of carbon atoms.
To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives: [ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
To calculate the number of molecules in 15 grams of ethane (C2H6), first find the molar mass of C2H6, which is 30.07 g/mol. Next, calculate the number of moles in 15 grams using the formula: moles = mass / molar mass. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
moles = mass/relative atomic mass 1 = mass/12 mass = 12 x 1 = 12 grams
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.
The mass of carbon in carbon dioxide is 12 grams per mole.
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ratio of isotopes equal to that in nature - has a mass of 12.0107 grams.
The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6
The mass of 4,5 moles of carbon is 54,04815 g.
We use the equation: Mass = Number of moles * Molecular or atomic mass Since the number of moles is 1 ("one mole of carbon-12 atoms") and the atomic mass of carbon-12 atoms is 12, hence the mass would be 12 grams. Note that the unit grams (g) is used here, as it is the SI unit for mass measurement. I hope this is useful! :)
1/(6.02214 x 1023) = 1.66054*10-24 molesC-atoms= 1 C-atom