To find the number of moles of carbon (C) in 32.6 g of ethane (C2H6), first calculate the molar mass of C2H6, which is approximately 30.07 g/mol. Since each molecule of C2H6 contains 2 moles of carbon, the total number of moles of C in 32.6 g of C2H6 can be found by dividing the mass by the molar mass and then multiplying by 2. This gives:
[ \text{Moles of C} = \left(\frac{32.6 , \text{g}}{30.07 , \text{g/mol}}\right) \times 2 \approx 2.16 , \text{moles of C}. ]
The answer is 2,17 moles carbon.
The combustion of ethane (C2H6) can be represented by the balanced chemical equation: [ \text{C}_2\text{H}_6 + 7/2 \text{O}_2 \rightarrow 2 \text{CO}_2 + 3 \text{H}_2\text{O} ] From this equation, we can see that 1 mole of ethane produces 2 moles of carbon dioxide (CO2). Therefore, the combustion of 1.00 mole of C2H6 will produce 2.00 moles of CO2.
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
1,4 moles carbon monoxide are produced.
The combustion reaction of ethane (C2H6) with oxygen produces carbon dioxide and water. The balanced equation for the combustion of ethane is: [ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} ] From the equation, 2 moles of ethane produce 6 moles of water. Therefore, 4 moles of ethane will produce ( \frac{6}{2} \times 4 = 12 ) moles of water.
The answer is 2,17 moles carbon.
The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor. 500 mol C2H6 x 2 mol C = 1000 mol C ........................1 mol C2H6
To find the mass of carbon in C2H6, we first need to calculate the molar mass of C2H6. Carbon has a molar mass of 12 g/mol, and hydrogen has a molar mass of 1 g/mol. The molar mass of C2H6 is (212) + (61) = 30 g/mol. The mass of carbon in 350 grams of C2H6 is then (2*12)/30 * 350 = 140 grams.
To find the number of carbon atoms in 77.28g of ethane (C₂H₆), first calculate the number of moles of ethane by dividing the mass by its molar mass (30.07 g/mol). Then, since each molecule of ethane contains 2 carbon atoms, multiply the number of moles by Avogadro's number (6.022 x 10²³) to find the number of carbon atoms.
'c' C2H6 ( Ethane) The others are INORGANIC Molecules. Remember , organic chemicstry deals with the chemistry or CARBON compounds. If no carbon is present then it is INORGANIC.
The molar mass of an element is its atomic weight in grams. The atomic weight is on the periodic table. 1 mole C = 12.0107 g C. To calculate the number of moles in 80 g of C, do the following: 80 g C x (1 mole C/12.0107 g C) = 6.66 mole C = 7 mole C* *This answer has been rounded to the proper number of significant figures. When multiplying or dividing, the answer is rounded to the fewest significant figures used in the calculation. 80 only has one significant figure. Refer to the related link below concerning significant figures.
How many moles of C are needed to react with 0.490 mole SO2?
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
Compound c, C2H6, is a hydrocarbon. It consists of only carbon and hydrogen atoms, which are the defining characteristic of hydrocarbons. The other compounds listed contain oxygen in addition to carbon and hydrogen.
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
1,4 moles carbon monoxide are produced.
The combustion reaction of ethane (C2H6) with oxygen produces carbon dioxide and water. The balanced equation for the combustion of ethane is: [ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} ] From the equation, 2 moles of ethane produce 6 moles of water. Therefore, 4 moles of ethane will produce ( \frac{6}{2} \times 4 = 12 ) moles of water.