ok... im too lazy to balance it myself. im assuming u already know how to balance equations. BUT heres a tip:
make a chart like this:
Elements: > Before: > After:
C* > 4 > 1
H* > 1 > 2
O > 3 > 3
so, when u do this, u can easily see what needs to be done. when u try a coefficient, make a new chart for it. the starred ones are the ones that need to be balanced.
oh, and one more thing: i assumed the numbers in there were all subscripts (i.e. 123) and i did not know what to do with the number "0".
2h2s+o2-->2h2o+co2
C2H6S PLUS O2 into CO2 plus H2O plus SO2
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
C2h5oh+3o2---------->2co2+3h2o
Balance c6h10o5 plus o2 yield to co2 plus h20? This is an equation for combustion of an or organic compound C6H10O5… +… O2.. =.. CO2.. +..H2O . Always balance C's first C6H10O5… +… O2.. =.. 6CO2.. +..H2O . balance H's next C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O balance O's last, but don't place a coefficient in front of the CO2 C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O ……5.O's…………..…=….12.O's ……5.O's ……5.O's…………..…=…….…17.O's ..17 - 5 = 12 O's needed on left side. 12.O's = 6 O2"s C6H10O5… +…6 O2.. à.. 6.CO2.. +..5.H2O Check it out …..Left………..Right C….6…………6 H….10……….10 O….17………..17
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
Yes.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
2h2s+o2-->2h2o+co2
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
The chemical equation is:C4H9OH + 6 O2 = 4 CO2 + 5 H2O
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
C2H6S PLUS O2 into CO2 plus H2O plus SO2
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
C2h5oh+3o2---------->2co2+3h2o
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
C3h8 + 5o2 -> 3co2 + 4h2o