ok... im too lazy to balance it myself. im assuming u already know how to balance equations. BUT heres a tip:
make a chart like this:
Elements: > Before: > After:
C* > 4 > 1
H* > 1 > 2
O > 3 > 3
so, when u do this, u can easily see what needs to be done. when u try a coefficient, make a new chart for it. the starred ones are the ones that need to be balanced.
oh, and one more thing: i assumed the numbers in there were all subscripts (i.e. 123) and i did not know what to do with the number "0".
To balance the equation C6H12 + O2 → CO2 + H2O, first balance the carbon atoms by putting a coefficient of 6 in front of CO2. Then balance the hydrogen atoms by putting a coefficient of 6 in front of H2O. Finally, balance the oxygen atoms by putting a coefficient of 9 in front of O2. The balanced equation is: C6H12 + 9O2 → 6CO2 + 6H2O
Balance c6h10o5 plus o2 yield to co2 plus h20? This is an equation for combustion of an or organic compound C6H10O5… +… O2.. =.. CO2.. +..H2O . Always balance C's first C6H10O5… +… O2.. =.. 6CO2.. +..H2O . balance H's next C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O balance O's last, but don't place a coefficient in front of the CO2 C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O ……5.O's…………..…=….12.O's ……5.O's ……5.O's…………..…=…….…17.O's ..17 - 5 = 12 O's needed on left side. 12.O's = 6 O2"s C6H10O5… +…6 O2.. à.. 6.CO2.. +..5.H2O Check it out …..Left………..Right C….6…………6 H….10……….10 O….17………..17
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
To balance octane (C8H18) with oxygen (O2) to form CO2 and H2O, you first write the unbalanced equation: C8H18 + O2 -> CO2 + H2O. Then balance the carbons by adding coefficients: C8H18 + 12.5O2 -> 8CO2 + 9H2O. The coefficients ensure the same number of each type of atom on both sides of the equation, fulfilling the law of conservation of mass.
This is a balanced chemical equation for the combustion of ethanol (C2H5OH) in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O): C2H5OH + 3O2 → 2CO2 + 3H2O
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
To balance the equation C6H14 + O2 -> CO2 + H2O, start by balancing the carbon atoms. This requires putting a coefficient of 6 in front of CO2. Next, balance the hydrogen atoms by adding a coefficient of 7 in front of H2O. Finally, balance the oxygen atoms by adjusting the coefficient in front of O2, which in this case is 9.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
The chemical equation is:C4H9OH + 6 O2 = 4 CO2 + 5 H2O
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
To balance the combustion reaction of pentadiyne (C5H2) with oxygen (O2), producing carbon dioxide (CO2) and water (H2O), you start by writing the unbalanced equation: C5H2 + O2 → CO2 + H2O. The balanced equation is: 2 C5H2 + 13 O2 → 10 CO2 + 2 H2O. This ensures that there are equal numbers of each type of atom on both sides of the equation.
The balanced equation for the reaction of C6H12O6 with O2 to form CO2 and H2O is: C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O
The balanced chemical equation for cellular respiration is C6H12 O6+ O2--> CO2 + H20 + ATP
C3h8 + 5o2 -> 3co2 + 4h2o