Balance c6h10o5 plus o2 yield to co2 plus h20?
This is an equation for combustion of an or organic compound
C6H10O5… +… O2.. =.. CO2.. +..H2O
.
Always balance C's first
C6H10O5… +… O2.. =.. 6CO2.. +..H2O
.
balance H's next
C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O
balance O's last, but don't place a coefficient in front of the CO2
C6H10O5… +… O2.. =.. 6.CO2.. +..5.H2O
……5.O's…………..…=….12.O's ……5.O's
……5.O's…………..…=…….…17.O's ..17 - 5 = 12 O's needed on left side.
12.O's = 6 O2"s
C6H10O5… +…6 O2.. à.. 6.CO2.. +..5.H2O
Check it out
…..Left………..Right
C….6…………6
H….10……….10
O….17………..17
Write the equation: C9H20 + O2 -> CO2 + H2O
Balance the carbons: C9H20 + O2 -> 9CO2 + H2O
Balance the hydrogens: C9H20 + O2 -> 9CO2 + 10H2O
Balance the oxygens: C9H20 + 14O2 -> 9CO2 + 10H2O
Add the state symbols: C9H20 (s) + 14O2 (g) -> 9CO2 (g) + 10H2O (l)
You have balanced the equation.
This chemical formula is balanced as follows:
2C10H22 + 31O2 → 20CO2 + 22H2O
c9H20+o2 balance
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
C2H6S PLUS O2 into CO2 plus H2O plus SO2
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
6 CO2 + 12 H2O --> C6h12O6 + 9 O2
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
2 PbO + C -> 2 Pb + CO2
The correct answer is co2+c= 2co
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
C3h8 + 5o2 -> 3co2 + 4h2o
3H2C2O4 + 2K2MnO4 = 6CO2 + 2K2O + Mn2O3 + 3H2O
2 NaHCO3 = Na2CO3 + CO2 + H2O.
C+co2 = 2co
C9H20 + 14(O2) = 9(CO2) + 10 (H2O) and that's all there is to it
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
Cs2 + 3o2 ------->>> co2 + 2so2
C2H6S PLUS O2 into CO2 plus H2O plus SO2
co2 + c = 2co I'm guessing you meant to say 'equals' after the c, because if there wasn't a yield/equal sign, you can't balance it.