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This problem is a Double Reactant. "K+ H20 ----> KOH + H2" would equal "2K + 2H20 ---> 2KOH + H2"

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14y ago
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12y ago

2KOH + 2K = 2K2O + H2 (400-450° C).

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Q: How do you balance K plus H20---KOH plus H2?
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ANSWERED How many g of potassium must react with H20 to produce 1.60 L of H2 at STP according to the following equation?

You need the balanced chemical reaction equation :------------------------------------------------------------------------2 K + 2 H2O ----. 2 KOH + H2moles H2 = n H2 = ( 1.60 L ) ( 1 mol H2 / 22.4 L H2 ) = 0.07143 moles H2moles K = n K = ( 0.07143 mol H2 ) ( 2 mol K / 1 mol H2 ) = 0.14286 moles Kmass K = m K = ( 0.14286 mol K ) ( 39.10 g K / mol K )mass K = m K = 5.56 g of potassium