This problem is a Double Reactant. "K+ H20 ----> KOH + H2" would equal "2K + 2H20 ---> 2KOH + H2"
2KOH + 2K = 2K2O + H2 (400-450° C).
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2 k + h2so4 = k2so4 + h2
Balanced :2 K + 2 H2O ----> 2 KOH + H2
It's K + H2SO4= K2SO4 +H2
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
2K+2HCl-->2KCl+H2
2 k + h2so4 = k2so4 + h2
Balanced :2 K + 2 H2O ----> 2 KOH + H2
k+h2o>koh+h2
It's K + H2SO4= K2SO4 +H2
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
Balanced equation: 2 H2 + O2 --> 2 H2O
2K+2HCl-->2KCl+H2
2 K + Br2 -> 2 Kbr
For the reaction 2HCl(g) ==> H2(g) + Cl2(g), the Keq = [H2(g)][Cl2(g)]/[HCl(g)]^2
Balanced:2 K + Br2 ----> 2 KBr
2K + 2H2O --> 2KOH + H2 The balanced equation shows that there is a 2 in front of water.
You need the balanced chemical reaction equation :------------------------------------------------------------------------2 K + 2 H2O ----. 2 KOH + H2moles H2 = n H2 = ( 1.60 L ) ( 1 mol H2 / 22.4 L H2 ) = 0.07143 moles H2moles K = n K = ( 0.07143 mol H2 ) ( 2 mol K / 1 mol H2 ) = 0.14286 moles Kmass K = m K = ( 0.14286 mol K ) ( 39.10 g K / mol K )mass K = m K = 5.56 g of potassium