The reaction is:
4Na + TiCl4 = Ti + 4NaCl
The cation, or positively charged ion, in NaCl is Na+.
The equation is: NaCl----------Na++ Cl-
NaCl---------------→Na+ + Cl-
Na+ + Cl- --> NaCl NaCl = salt.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
To balance the equation Cl₂ + 2NaI -> 2NaCl + I₂ you need to ensure that the number of each element is the same on both sides of the equation. In this case, you balance the equation by adding a coefficient of 2 in front of NaCl and I₂ to balance the number of atoms of Na, Cl, and I.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
Here is the balanced equation! TiCl4 + 2H2O --> TiO2 + 4HCl
To balance an equation involving sodium (Na) and phosphate (PO4), ensure the number of sodium atoms is equal on both sides by adding coefficients. For example, in the reaction Na3PO4 + CaCl2 -> Ca3(PO4)2 + NaCl, balance by adding a coefficient of 3 in front of NaCl to ensure equal numbers of sodium atoms on both sides.
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.
In NaCl, the molar mass of Na is 22.99 g/mol and Cl is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol. Given 8.0g of NaCl, the mass is distributed between Na and Cl in a 1:1 ratio. Thus, there are 3.5g of Na in 8.0g of NaCl.