How do you balance pb1o2 plus h2so4 yields pb1so4 plus h2o1?

Answer 1

I believe that there is a typo in the formula, because of the ionization state of the lead. In the reactant PbO2, each oxygen carries a -2 charge, so the Pb must be +4, but in the products, PbSO4 is the problem... The SO4 will carry a -2 charge, which means the lead must now be a +2, If the lead went from +4 to +2, it would have had to get 2 electrons from somewhere....

So, the equation is balanced if it is: PbO2 + 2H2SO4 ---> Pb(SO4)2 + 2H2O

or: PbO + H2SO4 ---> PbSO4 + H2O