With combustion equations always balance the O2 last.
C10H8 + 12O2 >> 10CO2 + 4H2O
6co2 + 4h2o = c6h8o6 + 5o2
C6h12 + 9o2 = 6co2 + 6h20
Al + O2 will never yield Fe2O3.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
AlBr2 + Cl = AlCl + Br2
Na2SO3 + 2HCl -> 2NaCl + H2SO3
2c + o2---2co
Al + O2 will never yield Fe2O3.
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
MgCl2
The chemical equation is:SF4 + 2 H2O = SO2 + 4 HF
plus sign
co2 + c = 2co I'm guessing you meant to say 'equals' after the c, because if there wasn't a yield/equal sign, you can't balance it.
This simple equation is: 2H2 + O2 = 2H2O
2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2
2H2 + 2NO --> 2H2O + N2
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
1,3,1,3
liho+h2s=