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oxygen
aluminium chloride and oxygen gas
Burning of aluminum in oxygen (air): 4Al + 3O2 → 2Al2O3
Aluminum loses three electrons to have a full valence shell. Oxygen gains two electrons to have a full valence shell. Aluminum Oxide is shown as Al2O3 because there are three oxygen atoms with a total of 6 gained electrons. Two Aluminum atoms lose 6 electrons and three Oxygen atoms gain six. This is the balance between aluminum and oxygen.
The reaction is:2 Mg + O2 = 2 MgO
i have no clue
aluminium oxide --------------> aluminium and oxygen electrolysis
Aluminium + Oxygen = Aluminium Oxide 2 Al + O2 = 2AlO2
oxygen
Si + O2 ----> SiO2
Radium oxide is RaO.
aluminium chloride and oxygen gas
2Al + 3CuSO4 = Al2(SO4)3 + 3Cu
No. If you mean 4Al3O2. And If you mean 4Al + 3O2 ------> AL2O, it is still not balance.
Burning of aluminum in oxygen (air): 4Al + 3O2 → 2Al2O3
4Al(s) +302(g) ----> 2Al2O3(s)
Which of the billions of possible equations that contain aluminum are you asking about?