The balanced equation for aluminum and oxygen is: 4Al + 3O2 -> 2Al2O3. This balanced equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
The word equation for aluminum forming its protective layer is: Aluminum + Oxygen → Aluminum oxide.
Burning of aluminum in oxygen (air): 4Al + 3O2 → 2Al2O3
The correct chemical equation is 4Al + 3O2 -> 2Al2O3, which represents the reaction where aluminum combines with oxygen gas to form aluminum oxide.
The reaction between aluminum and oxygen forms aluminum oxide. The balanced chemical equation for this reaction is 4Al + 3O2 → 2Al2O3.
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
To balance the equation for the reaction of aluminum (Al) with oxygen (O2) to form aluminum oxide (Al2O3), we start with the unbalanced equation: 4Al + 3O2 → 2Al2O3. The coefficient on Al is 4 in this balanced equation, indicating that four aluminum atoms are needed to react with three molecules of oxygen to produce two formula units of aluminum oxide.
The word equation for aluminum forming its protective layer is: Aluminum + Oxygen → Aluminum oxide.
aluminium oxide --------------> aluminium and oxygen electrolysis
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Burning of aluminum in oxygen (air): 4Al + 3O2 → 2Al2O3
The chemical equation 2Al2O3 represents the reaction of two aluminum atoms with three oxygen atoms to form two molecules of aluminum oxide. This equation shows that for every two moles of aluminum, three moles of oxygen are required to form two moles of aluminum oxide.
The correct chemical equation is 4Al + 3O2 -> 2Al2O3, which represents the reaction where aluminum combines with oxygen gas to form aluminum oxide.
The reaction between aluminum and oxygen forms aluminum oxide. The balanced chemical equation for this reaction is 4Al + 3O2 → 2Al2O3.
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
To balance the equation Al + O2 -> Al2O3, first write out the unbalanced equation. Then balance the atoms one at a time, starting with the least common elements. In this case, balance aluminum first by adding a coefficient of 4 in front of Al on the left side. Then balance oxygen by adding a coefficient of 3 in front of O2 on the left side. The balanced equation is 4Al + 3O2 -> 2Al2O3.
To balance the chemical equation, the chemical formula O₂ indicates two oxygen atoms bonded together. The number of O₂ molecules needed to balance the equation would depend on the number of oxygen atoms present on both sides of the equation.
The ionic compound Al2O2 forms when aluminum reacts with oxygen.