4Al + 3O2 ---> 2Al2O3
You need 4Al and 3O2 This will give you 2 Al2O3
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
To balance the chemical equation Al2(SO4)3 + Al(OH)3 → H2SO4, we need to start by writing out the unbalanced equation: Al2(SO4)3 + Al(OH)3 → H2SO4 + Al(OH)3. The balanced equation is 2Al2(SO4)3 + 6Al(OH)3 → 3H2SO4 + 8Al(OH)3. This balances the number of atoms of each element on both sides of the equation.
The oxidation number of Al in Al2Br6 is +3. Each bromine atom has an oxidation number of -1, and since the compound is neutral, the sum of the oxidation numbers must equal zero. Hence, each Al atom must have an oxidation number of +3 to balance the -6 from the bromine atoms.
The balanced equation is: 4Al + 3O2 → 2Al2O3.
It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
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You need 4Al and 3O2 This will give you 2 Al2O3
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
2Al+3S--->Al2S3
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
To balance the equation Al + Fe3N2 -> AlN + Fe, you need to make sure that the number of each type of atom is the same on both sides of the equation. First, balance the Al by putting a coefficient of 2 in front of AlN to match the 2 Al atoms in Fe3N2. Next, balance the Fe by putting a 3 in front of Fe on the product side to match the 3 Fe atoms in Fe3N2. The balanced equation is: 2Al + 3Fe3N2 -> 2AlN + 9Fe.
To balance the chemical equation for the reaction of Al and Fe2O3 to produce Al2O3 and Fe, you need to ensure that the number of atoms for each element is the same on both sides of the equation. First, write the unbalanced equation: Al + Fe2O3 -> Al2O3 + Fe. Then, adjust the coefficients of each compound until the number of atoms of each element balances out. Solution: 2Al + Fe2O3 -> Al2O3 + 2Fe.
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To balance the chemical equation Al2(SO4)3 + Al(OH)3 → H2SO4, we need to start by writing out the unbalanced equation: Al2(SO4)3 + Al(OH)3 → H2SO4 + Al(OH)3. The balanced equation is 2Al2(SO4)3 + 6Al(OH)3 → 3H2SO4 + 8Al(OH)3. This balances the number of atoms of each element on both sides of the equation.
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The oxidation number of Al in Al2Br6 is +3. Each bromine atom has an oxidation number of -1, and since the compound is neutral, the sum of the oxidation numbers must equal zero. Hence, each Al atom must have an oxidation number of +3 to balance the -6 from the bromine atoms.