Take the amount of kWh that the meter states that you have used and multiply it by the cost of a kWh in your area.
Another Answer
Subtract the energy meter reading from the previous billing period from that from the current billing period to determine the number of kilowatt hours used during that period. Multiply this difference by the cost per kilowatt hour charged by your energy provider. Note, however, some energy providers have a complicated billing system (tariff) in which the cost per kilowatt hour changes according to the amount of energy you use: x cents per kilowatt hour for the first so many kilowatt hours, y cents per kilowatt hour for the next so many kilowatt hours, and so on. Additionally, there may be a multiplication factor based on the changing price of fuel.
If, Ct value = 50 meter unit = 30 so, 50 x 30 = 1500 kwh
How do you calculate mf with this following ct ratio 1. 75/5A, VA 5, Class 5.0, 660v. 2. 250/5A, VA 10, Class 1.0, 660V 3. 3200/5A, VA15, Class 1, 660v the meter ratio is 5/5A.
9 ct gold is hallmarked at 375, 14 ct 585, 18 ct 750 and 99% pure - 999. I could not find a 325. Using the above system I would guess that the 325 would be less than 9 ct.
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Its carats
mf is ratio of CT ration of meter box to CT ration written on meter. ex: CT meter box: 30/5, Meter ct ration 1/1. MF : (30/5)/(1/1)= 6
multiplying factor = Line CT Ratio / Meter CT Ratio Usually it is mentioned on Meter that MF = 1 if CT Ratio is 200/5 or MF = 2 if CT Ratio is 400/5. There can be an additional multiplication factor that would be mentioned on the meter.
If, Ct value = 50 meter unit = 30 so, 50 x 30 = 1500 kwh
It's given by f=ks, where k=2 and s=9
The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.
Multiplication factor can be derived from Meter CT, Meter PT, Connected CT and Connected PT values.
long travelling and cross travelling meter
K=(voltmeter range*ammeter range*power factor)/wattmeter range
is 3 phase Meter electicity to for the measurement of elektricity 3 phase.
How do you calculate mf with this following ct ratio 1. 75/5A, VA 5, Class 5.0, 660v. 2. 250/5A, VA 10, Class 1.0, 660V 3. 3200/5A, VA15, Class 1, 660v the meter ratio is 5/5A.
CT metering circuit can not be used to measure voltage
The maximum current output of a CT is 5 amps. Connected to a meter this will be full scale. What ever the ratio of the CT will dictate the scale face on the meter. A 500 amp CT's output will be 5 amps at 500 amps on the buss. 250 amps on the buss, the CT will output 2.5 amp or half scale on the meter face.