is 3 phase Meter electicity to for the measurement of elektricity 3 phase.
To calculate the current transformer (CT) ratio for a meter measuring kilowatt-hours (kWh), you need to know the primary current (the actual current flowing in the circuit) and the secondary current (the output current from the CT). The CT ratio is given by the formula: CT Ratio = Primary Current / Secondary Current. Once you have the CT ratio, you can use it to convert the readings from the secondary side to the primary side, which is essential for accurate energy measurement in kWh. Finally, ensure that the meter is calibrated according to the CT ratio for accurate readings.
A current transformer has to have the same ratio as the meter that it drives. Full scale deflection on the meter is 5 amps which equals the maximum allowed current on the phase that it is reading. A different ratio on the CT to meter would show an erroneous reading on the meter depending on the ratio of the connected CT. To keep costs down the meter is common to all three phases and is read by connecting the meter to the phase CT through a three position switch.
The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.
The 0.2S class is more accurate in meter reading than the 0.2 class. The 0.2S class is now mandatory for all meter reading.
A CT, or current transformer, has a specified current ratio. The 5 in your question is the current supplied to the metering instrument at full scale. CT's current ratio is always full scale to 5, for instance - 200:5, 3000:5, etc.So, if a CT has a ratio of, say, 1000:5, this means when the conductor being measured is supplying 1000 amperes to the load, the CT will output 5 amperes to the instrumentation. The relationship is linear, so if the current is 500 amperes, the output will be 2.5 amperes, at 200 amperes the output will be 1 ampere, etc.This is done so the instrument can be designed always the same, with a 5 ampere input, no matter what size current is to be measured. Otherwise you would have to order (and manufacture) many different models of meter, one for each current range.The metering must be set, or programmed, with the CT multiplier, so it knows how much current is really flowing when it sees 5 amperes on the input.Similarly, we use PT's or potential transformers to reduce higher system voltages to a range that the instrument can also handle.
Multiplication factor can be derived from Meter CT, Meter PT, Connected CT and Connected PT values.
mf is ratio of CT ration of meter box to CT ration written on meter. ex: CT meter box: 30/5, Meter ct ration 1/1. MF : (30/5)/(1/1)= 6
To calculate the current transformer (CT) ratio for a meter measuring kilowatt-hours (kWh), you need to know the primary current (the actual current flowing in the circuit) and the secondary current (the output current from the CT). The CT ratio is given by the formula: CT Ratio = Primary Current / Secondary Current. Once you have the CT ratio, you can use it to convert the readings from the secondary side to the primary side, which is essential for accurate energy measurement in kWh. Finally, ensure that the meter is calibrated according to the CT ratio for accurate readings.
long travelling and cross travelling meter
A current transformer has to have the same ratio as the meter that it drives. Full scale deflection on the meter is 5 amps which equals the maximum allowed current on the phase that it is reading. A different ratio on the CT to meter would show an erroneous reading on the meter depending on the ratio of the connected CT. To keep costs down the meter is common to all three phases and is read by connecting the meter to the phase CT through a three position switch.
multiplying factor = Line CT Ratio / Meter CT Ratio Usually it is mentioned on Meter that MF = 1 if CT Ratio is 200/5 or MF = 2 if CT Ratio is 400/5. There can be an additional multiplication factor that would be mentioned on the meter.
The ratio would be a 50:1 current transformer.
To test a current transformer (CT) with a Fluke meter, you'll first need to set the meter to the appropriate AC current setting. Connect the meter leads to the secondary terminals of the CT while ensuring the primary circuit is energized safely. Measure the output current; it should reflect the expected ratio based on the CT's specifications. If the reading is significantly different from expected, the CT may be faulty or improperly connected.
CT metering circuit can not be used to measure voltage
The maximum current output of a CT is 5 amps. Connected to a meter this will be full scale. What ever the ratio of the CT will dictate the scale face on the meter. A 500 amp CT's output will be 5 amps at 500 amps on the buss. 250 amps on the buss, the CT will output 2.5 amp or half scale on the meter face.
A CT multiplier is the ratio of current trough a CT to the output of a CT. Example: A 200/5 Multiplier means that the cable passing through the CT must see 200A to provide a 5A output to the reading meter. The reading meter will then display 200A on it's display but it of course is only seeing 5A itself. Many digital meters have selectable Multipliers so you don't have to stock a wide selection of meters.
The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.