How do you want to report the energy? Energy is expressed in Joules. A Joule is a coulomb times the voltage. You will need to do the multiplication.
If its' unplugged then the only energy would be from the battery which is about 3 Volts.
There is no "unit of electricity" metric or otherwise. There are units of measurement for electric charge (coulombs), potential (volts), current (amperes), energy (joules) and power (watts).
Electrical current is the number of elementary charge units (coulombs) that pass by a given point in one second. Current, measured in amperes, is coulombs per second. Electrical voltage is the "pressure" behind that current. Voltage, measured in volts, is joules per coulomb.
No. You cannot use any battery for it.
1.5 volts
It takes 31.5 joules for 12 volts to move 2.5 coulombs. Volts is joules per coulomb. The rest is just algebra, i.e. joules is coulombs times volts, 2.5 times 12 is 31.5.
Amps are coulombs per second, and there is no information on rates given here.
The potential difference in a battery is like the height of the stairs. The amount of charge separated in a battery is like the mass moved up the stairs. The potential energy in the battery is due to both the potential difference (volts) and the amount of charge that has been separated (coulombs).
The battery can move a charge of 100,000 coulombs through a potential difference of 12 volts, therefore the energy released is 12 x 100,000 coulombs, or 1.2 Megajoules. 100,000 coulombs is (for example) 10 Amps for 10,000 seconds, in other words 10 amps for 2.78 hours, so its capacity is 27.8 ampere-hours.
Electromagnetic is energy involving electric and magnetic fields. E= VC + IWb where V is volts and C is Coulombs and I is Amperage and Wb is Webers.
If its' unplugged then the only energy would be from the battery which is about 3 Volts.
For the backup time for 4 fans. First we required battery AH (battery amper) and battery volts & and and ups ratings. then we calculate back time .
To calculate the energy expended in moving a charge through a potential difference, you can use the formula: Energy (E) = Charge (Q) × Potential Difference (V) Given: Charge (Q) = 20 Coulombs Potential Difference (V) = 0.5 Volts Plugging in the values: E = 20 C × 0.5 V E = 10 Joules Therefore, the energy expended in moving a 20 Coulomb charge through a potential difference of 0.5 Volts is 10 Joules.
Battery, resistor, and capacitor are connected in series. E = voltage of the battery, volts R = resistance of the resistor, ohms C = capacitance of the capacitor, farads T = time since the circuit was completed, seconds I = current in the circuit, amperes Vc = voltage across the capacitor, volts Q = charge on the capacitor, coulombs e = base of natural logs = approx 2.7183 At any time 'T' after everything is connected up, Vc = E x (1 - e-T/RC) volts I = (E/R) e-T/RC amperes or I = (E - Vc) / R Q = 1/2 C Vc2 coulombs or Q = 1/2 C E2 (1 - e-T/RC )2 coulombs See ? Nothing to it.
A 12 volt is an amount of electric energy. This type of energy is usually stored inside of a battery.
There is no "unit of electricity" metric or otherwise. There are units of measurement for electric charge (coulombs), potential (volts), current (amperes), energy (joules) and power (watts).
The light-bulb will probably burn out if you connect it directly. Other than that, you CAN'T calculate the time duration based on the data provided. The duration depends on how much energy the light-bulb uses, and how much energy the batter is able to store. Voltage is NOT a unit of energy.