In words: The total conductance is the sum of the individual conductances. Since conductance is the reciprocal of resistance:
1/R = 1/R1 + 1/R2 + 1/R3...
where R is the combined (or equivalent) resistance, and R1, etc. are the individual resistances. In other words, you first take the reciprocal of the resistances, add everything up, then (to get the actual combined resistance), you take the reciprocal again.
Sample calculation: resistances are 2 and 3 Ohms.
1/R = 1/2 + 1/3
1/R = 3/6 + 2/6
1/R = 5/6
R = 6/5 or 1.2
Add the admittance, or inverse of the resistance.
Example 1: two 100 ohm resistors in parallel: 1/100 + 1/100 = 2/100 siemens, or 100/2 = 50 ohms.
Example 2: one 50 ohm, two 25, three 15 ohm resistors in parallel: 1/50 + 2/25 + 3/15 = 45/150 siemens, or 3.33 ohms.
Since I don't have the tools here to type math, I'll state it in plain english. The reciprocal of Total Resistance is equal to the sum of the reciprocals of the resistance of each leg.
Stated another way... 1/R(t) = 1/R(1) + 1/R(2) + 1/R(3)......
Guess I did have the tools to type this formula after all.
If the parallel legs are all equal resistance, it's easier... then R(t) = R/N where R = the resistance of each individual leg and N = the number of legs.
1/ Rt =1/ r1+1/r2+1/r3 +...1/Rn
If R1 and R2 are connected in parallel then its effective resistance R1*R2 /(R1+R2)
Suppose R1, R2 and R3 are connected in parallel, then the effective value will be
R1*R2*R3 /(R1R2+R2R3+R3R1)
if the total resistance r_total and the resistance of the parallel elements is r_1, r_2 etc
Then the total resistance is 1/r_total = 1/r_1 + 1/r_2 ....
If the parallel elements have capacitance or inductance, the resistances above can be replaced by impedances z_1, z_2 ....
1/R= 1/R+1/R+1/R.... The first R is total resistance and the other R's are the resistances of the individual resistors
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).
Parallel resistance refers to 2 or more resistors where the input sides are connected together and the output sides are connected together. The formula to calculate it is the inverse of the total resistance of the circuit is equal to the sum of the inverses of the individual resistances. 1/R (total) = 1/R (1) + 1/R (2) + 1/R (3) + …
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
Total equivalent resistance = reciprocal of (sum of reciprocals of each individual resistance)
In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.
It depends upon the resistance values. Series resistance is the summation of all of the resistances, but to calculate the parallel is more complicated. Once the total resistance of each configuration is known, find the total current for each then multiply the current by the source voltage and this will provide the power.
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).
No, the total resistance increases.
Total equivalent resistance = reciprocal of (sum of reciprocals of each individual resistance)
Parallel resistance refers to 2 or more resistors where the input sides are connected together and the output sides are connected together. The formula to calculate it is the inverse of the total resistance of the circuit is equal to the sum of the inverses of the individual resistances. 1/R (total) = 1/R (1) + 1/R (2) + 1/R (3) + …
"http://www.tpub.com/neets/book1/chapter3/1-26.htm" This site explains how to calculate the resistance, but it decreases the resistance when you add more.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
Total equivalent resistance = reciprocal of (sum of reciprocals of each individual resistance)
In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.
D. The total resistance is equal to the lowest resistance in the circuit