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the coupling of ATP hydrolysis to the production of a proton gradient across a membrane by a proton pump
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proton
11 protons and 12 neutrons
the electron would have the longer wavelength b/c the proton has more momentum and λ=h/p (λ is wavelength, h is planc's constant and p is momentum)
Here is how you calculate a coupling constant J: For the simple case of a doublet, the coupling constant is the difference between two peaks. The trick is that J is measured in Hz, not ppm. The first thing to do is convert the peaks from ppm into Hz. Suppose we have one peak at 4.260 ppm and another at 4.247 ppm. To get Hz, just multiply these values by the field strength in mHz. If we used a 500 mHz NMR machine, our peaks are at 2130 Hz and 2123.5 respectively. The J value is just the difference. In this case it is 2130 - 2123.5 = 6.5 Hz This can get more difficult if a proton is split by more than one other proton, especially if the protons are not identical.
Here is how you calculate a coupling constant J: For the simple case of a doublet, the coupling constant is the difference between two peaks. The trick is that J is measure in Hz, not ppm. The first thing to do is convert the peaks from ppm into Hz. Suppose we have one peak at 4.260 ppm and another at 4.247 ppm. To get Hz, just multiply these values by the field strength in mHz. If we used a 500 mHz NMR machine, our peaks are at 2130 Hz and 2123.5 respectively. The J value is just the difference. In this case it is 2130 - 2123.5 = 6.5 Hz This can get more difficult if a proton is split by more than one other proton, especially if the protons are not identical.
Here is how you calculate a coupling constant J: For the simple case of a doublet, the coupling constant is the difference between two peaks. The trick is that J is measured in Hz, not ppm. The first thing to do is convert the peaks from ppm into Hz. Suppose we have one peak at 4.260 ppm and another at 4.247 ppm. To get Hz, just multiply these values by the field strength in mHz. If we used a 500 mHz NMR machine, our peaks are at 2130 Hz and 2123.5 respectively. The J value is just the difference. In this case it is 2130 - 2123.5 = 6.5 Hz This can get more difficult if a proton is split by more than one other proton, especially if the protons are not identical.
Here is how you calculate a coupling constant J: For the simple case of a doublet, the coupling constant is the difference between two peaks. The trick is that J is measured in Hz, not ppm. The first thing to do is convert the peaks from ppm into Hz. Suppose we have one peak at 4.260 ppm and another at 4.247 ppm. To get Hz, just multiply these values by the field strength in mHz. If we used a 500 mHz NMR machine, our peaks are at 2130 Hz and 2123.5 respectively. The J value is just the difference. In this case it is 2130 - 2123.5 = 6.5 Hz This can get more difficult if a proton is split by more than one other proton, especially if the protons are not identical.
Protons are not coupling. Only electrons can coupled.
As far as I'm aware, it means that it looks like a triplet, but you don't expect a triplet. It's "really" a doublet of doublets, but the two coupling constants are too similar, so it looks like a triplet, as the two inner peaks merge.
the coupling of ATP hydrolysis to the production of a proton gradient across a membrane by a proton pump
1.0 amu
oxidative phosphorylation does not involve with the respiratory complex in the inner mitochondria membrane. Oxidative phosphorylation useful in generate the production of ATP from the proton gradient or proton motive force. Chemiosmotic coupling invilve the manner of ETC on how its create the proton gradient and the proton gradient is indirectly directed with the production of ATP.The proton gradient causes the conformational change of tigthly binding of ATP to open binding ATP .Then ATP can be released and be used to the metabolic cell needs and translocate the ATP to cytoplasm that can be used to phosphorylate substrate.
calculate the ratio between proton&electron
proton
The charge and mass ratio of proton is constant, the positive particles found during discharge tube experiment are nuclei of atoms which have different charge and mass ratio.