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Q: How do you calculate the force needed to pull a mass of 20gk at a uniform slow speed up a plane inclined at an angle of 30 with the horizontal if the coefficient of kinetic friction is 0.20?

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Incline the plane until breakaway is achieved and note the angle. > A) Sin angle * 5 = force down (and parallel to) the slope in kgf. > B) Cos angle * 5 = force (weight) of block normal to slope surface. > Static friction coefficient = A / B

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The easy answer to this question is to recognize that some of the potential energy will be lost to work against friction and this loss is simply the force of friction multiplied by the length of the ramp which is 6N. The previous answers I submitted are incorrect.

Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity

That depends on a variety of circumstances. Mainly:Whether you pull it horizontally or up an inclined surface; in the latter case, you need more force. If you go down an inclined surface, you may even need a force in the opposite direction to stop it.Also, on the coefficient of friction. Assuming a horizontal movement, you can make the force required become quite low - for example, if the object you want to move is on a cart with wheels, or if it rests on a well-lubricated surface.

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co -efficient of friction is equal to tan inverse of the inclination

(Coefficient of friction of plane ab) + 2(Coefficient of friction of plane bc) = 1 Coefficient of friction of plane ab = Coefficient of friction of plane bc = 1/3 = 0.33333......

Roll the object down an inclined plane. Adjust the angle so that the objects rolls down without sliding at a constant speed. When that happens, the tangent of the angle of the plane relative to the horizontal is the coefficient of rolling friction.

Yes, if the incline angle becomes great enough. > As the angle increases, the force on the object down the incline increases but the effective weight on the slope surface decreases. > When the object breaks away the angle of incline can be used to calculate the coefficient of friction between the two surfaces. > coefficient of friction = sine ( incline angle ) / cosine ( incline angle )

Incline the plane until breakaway is achieved and note the angle. > A) Sin angle * 5 = force down (and parallel to) the slope in kgf. > B) Cos angle * 5 = force (weight) of block normal to slope surface. > Static friction coefficient = A / B

Static friction does not apply when the block is already moving. Without friction, the force on the block parallel to the surface of the incline is Fg*sin(angle), so the acceleration without friction is 9.8* sin(30) = 9.8 * (1/2) = 4.9 Since it is accelerating at 3.2, friction is slowing down the block by (4.9-3.2 = 1.7). The coefficient of kinetic friction is (1.7/4.9) = 0.346939

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Place the object on the plane. Slowly increase the angle of the plane until the object begins to move at angle Θ. The µs = tan Θ. For µk, same process, but give the object a little push at each increasing value of Θ.

No. A flat surface which is horizontal is not an inclined plane.

The easy answer to this question is to recognize that some of the potential energy will be lost to work against friction and this loss is simply the force of friction multiplied by the length of the ramp which is 6N. The previous answers I submitted are incorrect.

Is mgsinΘ > μmgcosΘ ? Is sinΘ > μ cosΘ ? Is sin35º > .65 cos35º Is .573 > .532 => Yes, so crate slides down the plane, no matter what the mass is or acceleration due to gravity